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4 years ago

As the distance between two masses increases, the gravitational force of attraction between them

2 answers:

8 0

As the distance increases, the mutual gravitational forces between two objects DEcrease. That's why you're attracted toward the Earth more strongly than toward Jupiter. Or toward the sun.

storchak [24]4 years ago

6 0

Decreases. Coulomb's Law is based on this, and it basically says, as masses move further apart, their attraction forces become weaker. So, the answer is A.

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Why can concave mirror is used in cosmetic mirror

Marta_Voda [28]

A concave mirror is a curved mirror that bulges inward. Objects reflected in concave mirrors often appear bigger than they really are, although the specifics of how the image appears depends upon the object's distance from the mirror. Concave mirrors are used in car headlights, in dentist's offices and in makeup mirrors.

5 0

3 years ago

Consider a perfectly reflecting mirror oriented so that solar radiation of intensity I is incident upon, and perpendicular to, t

VLD [36.1K]

Answer:

Frad = 2IA/C

Explanation:

see attached file

4 0

3 years ago

Determine an appropriate size for a square cross-section solid steel shaft to transmit 260 hp at a speed of 550 rev/min if the m

Phantasy [73]

Answer:46.05 mm

Explanation:

Given

$Power=260\ hp\approx 260\times 746=193.96\ KW$

speed $N=550\ rev/min$

allowable shear stress $(\tau )_{max}=15\ kpsi\approx 103.421\ MPa$

Power is given by

$P=\frac{2\pi NT}{60}$

$193.96=\frac{2\pi 550\times T}{60}$

$T=3367.6\ N-m$

From Torsion Formula

$\frac{T}{J}=\frac{\tau }{r}-----1$

where J=Polar section modulus

T=Torque

$\tau$ =shear stress

For square cross section

$r=\frac{a}{2}$

where a=side of square

$J=\frac{a^4}{6}$

Substituting the values in equation 1

$\frac{3376.6}{\frac{a^4}{6}}=\frac{103.421\times 10^6}{\frac{a}{2}}$

$a=0.04605\ m$

$a=46.05\ mm$

7 0

3 years ago

A go-kart accelerates at a rate

stira [4]

Answer:

if it is at a speed of 12.5 m / s it would take 2 minutes

Explanation:

4 0

4 years ago

lf an object's velocity changes from 25 meters per second to 15 meters per second in 2.0 seconds, the magnitude of the object's

Mila [183]

Answer:

-5 m/s^2

Explanation:

$acceleration = \frac{change \: in \: velocity}{time} \\ \\ = \frac{15 - 25}{2} \\ \\ = \frac{ - 10}{2} \\ \\ = - 5 \: m {s}^{ - 2} \\ \\ negative \: sign \: represents \: that \: \\ object \: is \: slowing \: down.$

6 0

3 years ago

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