The owner could sell 27 sandwiches and 7 water bottles.
Answer:
The probability that the average score of the 49 golfers exceeded 62 is 0.3897
Step-by-step explanation:
The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5
![\mu = 61](https://tex.z-dn.net/?f=%5Cmu%20%3D%2061)
![\sigma = 3.5](https://tex.z-dn.net/?f=%5Csigma%20%3D%203.5)
We are supposed to find he probability that the average score of the 49 golfers exceeded 62.
Formula : ![Z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
![Z=\frac{62-61}{3.5}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7B62-61%7D%7B3.5%7D)
![Z=0.285](https://tex.z-dn.net/?f=Z%3D0.285)
Refer the z table for p value
p value = 0.6103
P(x>62)=1-P(x<62)=1-0.6103=0.3897
Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897
90/3=30 30*(15)=450 450 is your answer.
Answer:
It's going to be B and E because it's in the hundreds place not in the tens or whole
Answer:
3???
Step-by-step explanation: