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DanielleElmas [232]
3 years ago
11

54,000 families have incomes less than $20,000 per year. This number of families is 60% of the families that had this income lev

el 12 years ago. What was the number of families who had incomes less than 20,000 per year 12 years ago?
Mathematics
1 answer:
tangare [24]3 years ago
4 0
54000/.6= 90000, so answer should be 90,000
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The circumference of a circle is 18 pi feet. What is the area in terms of pi?
Nastasia [14]

Answer:

I am not sure if this is right but the answer is

The area of a circle with circumference 18π is 254.5

3 0
2 years ago
Decrease £120 by 45%
Dovator [93]
120 * 45  % =  120 *0,45  =  54 £

  120 -54 = 66 £





7 0
3 years ago
Read 2 more answers
Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame
lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{207.9 - 208}{0.1678}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0
3 years ago
It takes 2 1/3 hours to paint a wall. How long will it take to paint 7 walls at this rate?
boyakko [2]

Answer:

Hi! The correct answer is 49/2 as an improper fraction and 24 1/2 in mixed number form!

Step-by-step explanation:

<em><u>~If it takes 2 and 1/3 to paint 1 wall then that's the unit rate. Multiply the unit rate by the number of total walls and that's your answer~</u></em>

7 0
2 years ago
To estimate the number of people in Springfield, population 10,000, who have a swimming pool in their backyard, 250 people were
Andrei [34K]

Answer:

2400 people

Step-by-step explanation:

Let x be the number of people who had a swimming pool in the population of 10,000,

Thus, the ratio of people who had swimming pool to the total population = \frac{x}{10000}

Since, out of 250 people 60 had swimming pool,

So, the ratio of the people who had swimming pool to the total population = \frac{60}{250}

\because \frac{x}{10000}=\frac{60}{250}

\implies 250x=600000

\implies x=\frac{600000}{250}=2400

Hence, 2400 people in the city might one expect to have a swimming pool.

First option is correct.

8 0
3 years ago
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