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3 years ago

Marc was born on his grandmother’s 56th birthday. In how many years will Marcs grandmother be 5 times as Marc will be then?

Mathematics

1 answer:

galina1969 [7]3 years ago

4 0

Answer:

Therefore 70 year Marc's grandmother be 5 times of as Marc will be after (70-56) = 14 year.

Step-by-step explanation:

Given, Marc was born on his grandmother's 56th birthday.

Let , x year will Marc's grandmother be 5 times as Marc will be then.

At that time the age of Marc will be = (x-56) year

According to the problem,

x= 5(x-56)

⇔x = 5x - 280

⇔x-5x= -280

⇔-4x=-280

⇔x=70

Therefore 70 year Marc's grandmother be 5 times of as Marc will be after (70-56) = 14 year.

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Cuál es el resultado de |-15| x (-5)

notka56 [123]

Answer:

$\frac{15}{x^5}$

Step-by-step explanation:

$\left|-15\right|x^{-5}$

Step 1: Apply exponent rule: $\:a^{-b}=\frac{1}{a^b}$

$=\left|-15\right|\frac{1}{x^5}$

Step 2: Multiply fractions: $a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}$

$=\frac{1\cdot \left|-15\right|}{x^5}$

Step 3: Simplify

$=\frac{15}{x^5}$

The result is $=\frac{15}{x^5}$

Spanish/Espanól

Respuesta:

$\frac{15}{x^5}$

Explicación paso a paso:

$\left|-15\right|x^{-5}$

Paso 1: aplique la regla del exponente: $\:a^{-b}=\frac{1}{a^b}$

$=\left|-15\right|\frac{1}{x^5}$

Paso 2: multiplica fracciones: $a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}$

$=\frac{1\cdot \left|-15\right|}{x^5}$

Paso 3: simplifica

$=\frac{15}{x^5}$

El resultado es $=\frac{15}{x^5}$

7 0

3 years ago

Solve for 2. -9x +5 < 17 AND 13x + 25 < -1

Elena L [17]

Answer:

no solution

Step-by-step explanation:

-9x +5 < 17 AND 13x + 25 < -1

Solve each part separately and then put back together

-9x +5 < 17

Subtract 5 from each side

-9x+5-5< 17-5

-9x < 12

Divide each side by -9 remembering to flip the inequality

-9x/-9>12/-9

x > -4/3

and

13x + 25 < -1

subtract 25 from each side

13x +25-25 < -1-25

13x <-26

Divide by 13

13x/13 < -26/13

x <-2

There is no overlap so there is no solution

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