What is the value of X

The debate team is showing a video of their recent debate. The first showing begins at 3:15 p.m. The second showing starts at 4:

Ghella [55]

Given:
3:15 pm - start of first showing.
30 minutes break;
20 minutes late - 2nd showing.
4:50 - start of second showing.

4:50 - 0:20 = 4:30 should be the start of the second showing.
4:00 - 4:30 = 1/2 hour break
3:15 - 4:00 = duration of the 1st showing. 45 minutes in all.

4:50 + 0:45 = 5:35 pm end of the 2nd showing.

Yes, the 2nd showing will be over by 6:30 pm.

7 0

2 years ago

Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati

IrinaK [193]

Answer:

1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that $\mu = 6.6, \sigma = 1.1$

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

$Z = \frac{X - \mu}{\sigma}$

$-2.41 = \frac{X - 6.6}{1.1}$

$X - 6.6 = -2.41*1.1$

$X = 3.95$

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

The 100 - 0.8 = 99.2nd percentile, which is X when Z has a p-value of 0.992, so X when Z = 2.41.

$Z = \frac{X - \mu}{\sigma}$

$2.41 = \frac{X - 6.6}{1.1}$

$X - 6.6 = 2.41*1.1$

$X = 9.25$

The maximum head breadth that will fit the clientele is of 9.25-in.

8 0

2 years ago

Sal invests $16,000 at age 35. He hopes the investment will be worth $320,000 when he turns 40. If the interest compounds contin

Kaylis [27]

59.9%

Sorry I don’t have time to explain in the middle of an exam

3 0

2 years ago

Identify the hyperbolas (represented by equations) whose centers are at (2, 1)

weqwewe [10]

When the transverse axis is horizontal, a hyperbola centered at (h,k) has formula (x-h)^2/a^2-(y-k)^2/b^2=1. Plug in h=2, k=1, the formula is (x-2)^2/a^2-(y-1)^2/b^2=1 for some a,b. If the transverse axis is vertical, the formula is (y-h)^2/a^2-(x-k)^2/b^2=1, and (y-2)^2/a^2-(x-1)^2/b^2=1 in our case.

5 0

2 years ago

Which rational expression does not have any excluded values

Licemer1 [7]

What I understand is that if this are the three options that you put you should choose X2

4 0

2 years ago