Please Help!! 35 Points!!!

Here is a graph for one of the equations in the system of two equations.

skad [1K]

I believe that it is the second and third boxes

7 0

2 years ago

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How to i expand this ? x3 (3x - 5)

Nikitich [7]

Use the distributive formula

a(b - c) = ab - ac

$x^3(3x - 5) = \boxed{\bf{3x^4 - 5x^3}}$

5 0

3 years ago

Company A makes a large shipment to Company B. Company B can reject the shipment if they can conclude that the proportion of def

boyakko [2]

Answer:

$z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17$

The p value for this case would be given by:

$p_v =P(z>3.17)=0.00076$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

Step-by-step explanation:

Information provided

n=400 represent the random sample taken

X=59 represent number of defectives from the company B

$\hat p=\frac{59}{400}=0.1475$ estimated proportion of defectives from the company B

$p_o=0.1$ is the value to verify

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to verify if the true proportion of defectives is higher than 0.1 then the system of hypothesis are.:

Null hypothesis: $p \leq 0.1$

Alternative hypothesis: $p > 0.1$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17$

The p value for this case would be given by:

$p_v =P(z>3.17)=0.00076$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

8 0

3 years ago

4, 5, 3, 3, 1, 2, 3, 2, 4, 8, 2, 4, 4, 5, 2, 3, 6,2

Anna007 [38]

Answer:

Given data:

4, 5, 3, 3, 1, 2, 3, 2, 4, 8, 2, 4, 4, 5, 2, 3, 6,2

Put the data in the ascending order:

1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6, 8

Mean, the average:

(1 + 2*5 + 3*4 + 4*4 + 5*2 + 6 + 8)/18 = 3.5

Median, average of middle two numbers:

3

Mode, the most repeated number:

2 (repeated 5 times)

Mean is normally the best measure of central tendency, same applies to this data.

6 0

2 years ago

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The Malden family rented a car for $25.00 per day ,plus .25 cents per mile write an expression that represents the total cost of

Nikolay [14]

total cost = .25m + 25d

M is the number of miles driven and D is the number of days the car was rented

4 0

2 years ago

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