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2 years ago

Find the value of x in the figure below

Mathematics

2 answers:

zaharov [31]2 years ago

7 0

Step-by-step explanation:

this might help you out..

joja [24]2 years ago

6 0

I’m not sure but I added them up & combined like terms & got x=17.

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What is the slope of a line that is perpendicular to a line whose equation is 3y=−4x+2 ?

MAVERICK [17]

3y=−4x+2

y = -4x/3 + 2/3

y = 3x/4 + 2/3

so the slope is 3/4 remember that perpendicular slope is just the opposite reciprocal of the original slope given.

8 0

3 years ago

Determine whether the two expressions are equivalent. If so, tell what property is applied. If not, explain why. 7 · (6 · t) and

Georgia [21]

The two expressions are equivalent because the associative property of multiplication is applied, which means that no matter where you put the parenthesis, the two expressions will still be equal.

5 0

3 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

What is the slope of a l8ne that contains the points (34,12) and (32,48)

Vlad [161]

I hope this helps you

slope (34-32)= 12-48

slope.2= -36

slope = -18

7 0

3 years ago

Find the surface area of the tin game case

butalik [34]

To find the surface area you will need to find the area of all 5 surfaces (faces) on the prism. On a triangular prism there are 2 triangular faces and 3 rectangular faces. All 3 rectangular faces are the same and the 2 triangular faces are also the same.

To find the area of the triangular faces, you will use the formula for finding the area of a triangle:

A = 1/2bh
1/2 x 10 x 8.7
A = 43.5 in^2

To find the area of the rectangular faces, you will use the formula for finding the area of a rectangle:

A = bh
10 x 3
A = 30 in ^2

30 + 30 + 30 + 43.5 + 43.5 = 177

The minimum amount of wrapping paper needed for the gift is 177 square inches.

8 0

3 years ago