Answer:
E=
Joules
Step-by-step explanation:
1) Olá! Adicionando dados faltantes ao enunciado, como a fórmula dada:
e corrigindo a quantidade de Energia inicial:
Vamos seguir aplicando a fórmula, lembrando das propriedades de logaritmo.

Answer:
Step-by-step explanation:
Given that there are two vectors U = (-8,0,1)
V = (1,3,-3)
To find projection of u on V and also projection of V on U
First let us find the dot product U and V
U.V = 
Projection of U on V =
Similarly projection of V on U
=
2x+2=6
2x=4
x=2
Hope this helps :)
Answer:
-9/91
Step-by-step explanation:
-9/91
Answer:#carry on learning
Mark me as brainliest
hope it's help
The three undefined terms are point, line, and plane. Thus, figure D represents an undefined term as it's a line.