Answer:
fits under statistics category (also probability or math :\)
Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?
There 60 pints in 15 gallon
He needs 2 cups of sugar if he's tripling the recipe.
Answer:
x = 1
Step-by-step explanation:
We will represent the unknown number as x
10 - x = 8 + x
Add x to both sides
10 - x + x = 8 + x + x
10 = 8 + 2x
Subtract 8 from both sides
10 - 8 = 2x
2 = 2x
Divide both sides by 2
1 = x
x = 1
