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Effectus [21]
3 years ago
6

For $146.50, a cosmetician buys 5 L of moisturizer and repackages it in 125-milliliter jars. Each jar costs the cosmetician $0.4

0. Each jar of moisturizer is sold for $7.95. Find the profit on the 5 L of moisturizer.
Mathematics
1 answer:
LenaWriter [7]3 years ago
8 0

Answer:

The profit on 5 L moisturizer bottle is $797.25.

Step-by-step explanation:

The cost of 5 L of moisturizer bottle  = $146.50

The cost of each milliliter jar  = $0.40

Total number of small jars   = 125

⇒ The total Cost price of 125 jars  = 125 x Cost of each jar

                                                         = 125 x $0.40  = $50

So, the Total Cost Price = Cost of Big Bottle  +  Cost of small 125 bottles

                                        = $146.50 + $50  = $196.50

Now, Selling price of each jar = $7.95

⇒ The total Selling  price of 125 jars  = 125 x Selling price of each jar

                                                         = 125 x $7.95  = $993.75

Now Profit on 5 L bottle  =  TOTAL S.P - TOTAL C.P

=  $993.75  -  $196.50

= $797.25

Hence, the profit on 5 L moisturizer bottle is $797.25.

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The radius of the cone is 1.25 inches, and its height is 2.75 inches. If the diameter of the bubble gum ball is 0.5 inches, what
nasty-shy [4]
<h2>Explanation:</h2><h2></h2>

The volume of a cone can be found as:

V=\frac{1}{3}\pi r^2 h \\ \\ \\ Where: \\ \\ V:Volume \\ \\ r:radius \ of \ base \\ \\ h:height

Given the radius and height, we can find the volume of the cone:

V=\frac{1}{3}\pi r^2 h \\ \\ V=\frac{1}{3}\pi (1.25)^2(2.75) \\ \\ V=\frac{1}{3}\pi(1.5625)(2.75) \\ \\ V\approx 4.5in^3

The volume of a sphere is:

V=\frac{4}{3}\pi r^3 \\ \\ \text{Each gum ball has a diameter of 0.5in, so the radius is:} \\ \\ r=\frac{0.5}{2}=0.25in

So, for each gum ball the volume is:

V=\frac{4}{3}\pi r^3 \\ \\ V=\frac{4}{3}\pi (0.25)^3 \\ \\ V=0.065in^3

Therefore, the he closest approximation of the volume of the cone that can be filled with flavored ice is:

4.5-0.065=4.43in^3

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3 0
4 years ago
SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school are given below
kvasek [131]

Answer:

The value of test statistics is 25.

Step-by-step explanation:

We are given below the SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school;

380, 520, 480, 510, 560, 630, 670, 490, 500, 550, 400, 350, 440, 490, 620, 660, 700, 730, 740, 560

<em>Let </em>\sigma<em> = population standard of the reading and writing section SAT score of the students in this school</em>

So, Null Hypothesis, H_0 : \sigma \leq 100     {means that the reading and writing section SAT score of the students in this school is lesser than or equal to 100}

Alternate Hypothesis, H_A : \sigma<em> </em>> 100     {means that the reading and writing section SAT score of the students in this school is higher than 100}

The test statistics that would be used here is <u>One-sample Chi-square</u> test statistics;

                        T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2} __n_-_1

where, s^{2} = sample variance =  \frac{\sum (X-\bar X)^{2} }{n-1}  = 13135.8

            n = sample of 11th-grade students = 20

So, <u><em>the test statistics</em></u>  =  \frac{(20-1)\times 13135.8^{2} }{100^{2} }

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5 0
3 years ago
What is the answer of this question? ​
TEA [102]

9514 1404 393

Answer:

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Step-by-step explanation:

It turns out that the radical terms cancel, so the result is an integer. You can find the integer value using your calculator. It is ...

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The reciprocal of this is ...

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mr_godi [17]

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