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tangare [24]
2 years ago
8

a tour-bus operator sold $1,517 worth of tickets for a trip to Niagara Falls. Each tickets cost the same amount and could be pai

d for with three bills. What was the cost of a ticket
Mathematics
1 answer:
prisoha [69]2 years ago
3 0

We will make use of the concept of prime factors for solving this question. The prime factors of 1517 are:

1517=37\times 41

So, as can be clearly seen the Niagara Fall tour operator can either sell 37 tickets for $41 each or 41 tickets for $37 each.

Now, we know that we cannot reach $37 using just three bills. Thus, the only option left to us is $41 which can be broken down into three bills of $20,$20 and $1. This satisfies our condition.

Thus the cost of a ticket was $41 and 37 such tickets were sold.

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