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tangare [24]
3 years ago
8

a tour-bus operator sold $1,517 worth of tickets for a trip to Niagara Falls. Each tickets cost the same amount and could be pai

d for with three bills. What was the cost of a ticket
Mathematics
1 answer:
prisoha [69]3 years ago
3 0

We will make use of the concept of prime factors for solving this question. The prime factors of 1517 are:

1517=37\times 41

So, as can be clearly seen the Niagara Fall tour operator can either sell 37 tickets for $41 each or 41 tickets for $37 each.

Now, we know that we cannot reach $37 using just three bills. Thus, the only option left to us is $41 which can be broken down into three bills of $20,$20 and $1. This satisfies our condition.

Thus the cost of a ticket was $41 and 37 such tickets were sold.

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5. You are scheduling your classes for next year. There are 4 required classes: a physical education
puteri [66]
<h3>Answer:   450</h3>

==============================================

Explanation:

For now, let's consider we can only select 2 classes instead of 4. Let's say we only had to worry about PE and history.

Let A,B,C,D,E represent the five PE classes.

Let F,G,H,I,J,K represent the six history classes.

If you arrange the letters in a table, you should get 5*6 = 30 different inner boxes of the table. Refer to the diagram below.

Each two letter code in the table represents the 2 class combo. For example, BG means you picked PE class B and history class G.

This idea can be extend to selecting 3 classes. Imagine that each of the codes in the table are laid along the side of a new table. So we'd have a table of 30 rows. Then lay out 5 columns (say with letters L,M,N,O,P) to represent the 5 English classes. You would get a table of 30*5 = 150 different combos here. Of course you shouldn't actually make such a table since it's so large, but I'm simply just saying for you to imagine one. All of the tables mentioned are completely optional. A tree diagram is another way to organize things, though tree diagrams tend to get cumbersome.

Anyway, we would have 5*6*5 = 30*5 = 150 different ways to pick the PE, history and English classes. We can extend this out to include the math classes as well.

-------------------------

In short, all we do is multiply the given values together:

5*6*5*3 = 30*15 = 450

This idea is known as the counting principle.

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Step-by-step explanation:

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2 IS THE ONLY EVEN PRIME NUMBER   a prime number can only be divided by 1 or itself. 4 is a composite and 5 is a prime  hope this helps you.
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