Answer:
to what?
Step-by-step explanation:
To solve this
problem, let us first calculate for the Perimeter of the other octagon. The
formula for Perimeter is:
Perimeter = n * l
Where n is the number of sides (8) and l is the length of one
side. Let us say that first octagon is 1 and the second octagon is 2 so that:
Perimeter 2 = 8 * 16.35 in = 130.8 inch
We know that Area is directly proportional to the square of
Perimeter for a regular polygon:
Area = k * Perimeter^2
Where k is the constant of proportionality. Therefore we can
equate 1 and 2 since k is constant:
Area 1 / Perimeter 1^2 = Area 2 / Perimeter 2^2
Substituting the known values:
392.4 inches^2 / (87.2 inch)^2 = Area 2 / (130.8 inch)^2
Area 2
= 882.9 inches^2
<span>Therefore the area
of the larger octagon is about 882.9 square inches.</span>
Answer:
<h3>(x - 2)² + (y +8)² = 4</h3>
Step-by-step explanation:
<h3>Equation of circle:</h3>
Here, h , k are the co ordinates of the center and r is the radius
![\sf (x - 2)^2 + (y-[-8])^2 = 2^2\\\\(x - 2)^2 + (y + 8)^2= 4](https://tex.z-dn.net/?f=%5Csf%20%28x%20-%202%29%5E2%20%2B%20%28y-%5B-8%5D%29%5E2%20%3D%202%5E2%5C%5C%5C%5C%28x%20-%202%29%5E2%20%2B%20%28y%20%2B%208%29%5E2%3D%204)
Answer:
Step-by-step explanation:
area of the kite,
A=(d1*d2)/2
A=(16*21)/2= 168 in^2
choice C
A liter of water weighs 2.2 pounds
