Answer:
9:24 am
Step-by-step explanation:
89 bus = 8 minutes
368 bus = 12 minutes
Find the lowest common multiple(L.C.M) of 8 minutes and 12 minutes
8 minutes = 16, 24, 32, 40, 48
12 minutes = 24, 36, 48, 60
The L.C.M of 8 minutes and 12 minutes is 24 minutes
Both buses are at the same stop at 9 am.
The next time both buses will be at the same stand = 9 am + 24 minutes
= 9:24 am
we know that speed = distance/time
so renaldo speed = 3.2/0.5 = 6.4miles/hr (since time taken is 1/2 hr)
now after 1 hr of his appoinment i.e at 5:30pm he took bus whose speed is same as before i.e 6.4 miles/hr
now time taken to cover this 4.8 miles = 4.8/6.4 = 3/4 hr (since time = distance /speed )
3/4 hr = 3/4 * 60 = 45 minutes
so he reached at 6:15pm . so he will be on time.
BC is 8
DF is 4. This means that CE is 4 (it is a parallelogram)
CE and EB are congruent. This means that if CE if 4, EB is also 4
CE + EB = BC
4 + 4 = BC
BC = 8
hope this helps
