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evablogger [386]
3 years ago
15

How do you solve ln(x-4)+ln(6x-5)=ln5

Mathematics
1 answer:
astra-53 [7]3 years ago
4 0
X=(29+√481)/12. _____________________

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Find the area of this figure. Round your answer to the nearest hundredth. Use 3.14 to approximate
tatyana61 [14]

Answer:

104 ft²

Step-by-step explanation:

The area of the rectangle is represented by the following:

8ft x 10 ft = 80 ft

The area of the triangle is represented by the following:

(6ft x 8ft) divided by 2 = 24

By combining the values, you get 104 square feet.

3 0
2 years ago
Please help me with this i need a real answer not tjose file things
anyanavicka [17]

Answer:

c

Step-by-step explanation:

3 0
2 years ago
Write the square roots of 49 i in ascending order of the angle.
Troyanec [42]

Answer:

The square roots of 49·i in ascending order are;

1) -7·(cos(45°) + i·sin(45°))

2) 7·(cos(45°) + i·sin(45°))

Step-by-step explanation:

The square root of complex numbers 49·i is found as follows;

x + y·i = r·(cosθ + i·sinθ)

Where;

r = √(x² + y²)

θ = arctan(y/x)

Therefore;

49·i = 0 + 49·i

Therefore, we have;

r = √(0² + 49²) = 49

θ = arctan(49/0) → 90°

Therefore, we have;

49·i = 49·(cos(90°) + i·sin(90°)

By De Moivre's formula, we have;

r \cdot (cos(\theta) + i \cdot sin(\theta) )^{\dfrac{1}{2}}  =  \pm \sqrt{r} \cdot \left (cos\left (\dfrac{\theta}{2} \right ) + i \cdot sin\left (\dfrac{\theta}{2} \right ) \right )

Therefore;

√(49·i) = √(49·(cos(90°) + i·sin(90°)) = ± √49·(cos(90°/2) + i·sin(90°/2))

∴ √(49·i) = ± √49·(cos(90°/2) + i·sin(90°/2)) = ± 7·(cos(45°) + i·sin(45°))

√(49·i) = ± 7·(cos(45°) + i·sin(45°))

The square roots of 49·i in ascending order are;

√(49·i) = - 7·(cos(45°) + i·sin(45°))  and  7·(cos(45°) + i·sin(45°))

8 0
2 years ago
How many groups of 2.4 will divide into 29.52 ?
Bas_tet [7]
29.52/2.4 =12.3
 so 2.4 groups will go into 29.52, 12.3 times
3 0
3 years ago
Rectangle A measures 10 inches by 8 inches. Rectangle B is an enlarged copy of Rectangle A. Select all of the measurement pairs
Fudgin [204]

Answer:

See Explanation

Step-by-step explanation:

Given

Rectangle A:

Length: 10\ in

Width: 8\ in

Required

Determine the possible dimensions of Rectangle B

<em>The question has missing options; however, the question can still be solved.</em>

<em></em>

Rectangle B being an enlarged copy of A implies that the dimension of A A is enlarged in equal proportion to form B

Take for instance, the measurements of Rectangle B are

Length: 15 in

Width: 12 in

Divide the corresponding lengths of B by A to get the enlargement ratio

Ratio = \frac{B}{A}

For length:

Ratio = \frac{15}{10}

Ratio = 1.5

For width

Ratio = \frac{12}{8}

Ratio = 1.5

Notice that both ratios are the same.

For this measurement of B, we can conclude that B is an enlargement of A

Assume another measurements for B

Length: 20\ in

Width: 10\ in

Calculate Ratios

Ratio = \frac{B}{A}

For length:

Ratio = \frac{20}{10}

Ratio = 2

For width

Ratio = \frac{10}{8}

Ratio = 1.25

Notice that, both ratios are not equal.

For this measurement of B, we can conclude that B is not an enlargement of A

<em>Conclusively, all you have to do is: determine the ratios of the dimensions of B to A, if the result are equal then B is an enlarged copy of A; if otherwise, then B is not an enlarged copy</em>

5 0
3 years ago
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