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4 years ago

Using a cathode ray tube , what did Thomson confirm

Physics

2 answers:

Ira Lisetskai [31]4 years ago

8 0

Answer:

Its b

Explanation:

If ur on edgenuity!!

DiKsa [7]4 years ago

3 0

"J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged "soup." I looped this up, hoped it helped:)

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A hot-air balloon is descending at a rate of 2.3 m>s when a pas- senger drops a camera. If the camera is 41 m above the groun

zheka24 [161]

Answer:

a) t = 2.64s

b) Vf = -28.7m/s

Explanation:

If the balloon is descending, the velocity is -2.3m/s. So the equation to describe the postion of the falling camera is:

$Y = Vo*t - \frac{g*t^{2}}{2}$

$-41 = -2.3*t - \frac{10*t^{2}}{2}$ Solving for t, we get:

t1 = -3.1s and t2 = 2.64s We discard the negative time and use the positive one.

The velocity of the camera will be:

Vf = Vo - g*t = -2.3 - 10*2.64 = -28.7m/s

6 0

3 years ago

g a 240 V<0 source source supplies a balance, three-phase load in a delta configuration. The line current is 3 A<45. What

amid [387]

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8 0

3 years ago

A car slams on the brakes to stop. The road pushes back up on the car with a normal force of 12,750 N and friction from the brak

ivann1987 [24]

Answer:

$\displaystyle \mu_d=0.75$

Explanation:

Coefficients of Friction

Objects in physical contact produce friction which usually manifests as thermal energy being dissipated in the surface where the objects are interacting. It's usually harder to start to move an object from rest, that keeps moving it at a constant speed on the same surface. That is why there are two different coefficients of friction: the static and the dynamic. As mentioned, the static coefficient $\mu_s$ is greater than the dynamic coefficient $\mu_d$ . The car is already moving and is attempting to stop. The coefficient of friction is defined as

$\displaystyle \mu_d=\frac{F_r}{N}$

Where Fr is the force of friction and N is the normal or the force the road pushes back up on the car. With the given data, we have

$\displaystyle \mu_d=\frac{9,560\ N}{12,750\ N}$

$\displaystyle \boxed{\mu_d=0.75}$

The coefficient of friction is dimensionless (doesn't have any units)

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3 years ago

A person catches a ball with a mass of 145 g dropped from a height of 60.0 m above his glove. His hand stops the ball in 0.0100

natita [175]

Answer:

870N

Explanation:

momentum techniques

7 0

4 years ago

a bullet moving with a velocity of 100m/s pierce a block of wood and moves out with a velocityof 10 m/s.if the thickness of the

erma4kov [3.2K]

The emerging velocity of the bullet is 71 m/s.

The bullet of mass m moving with a velocity u has kinetic energy. When it pierces the block of wood, the block exerts a force of friction on the bullet. As the bullet passes through the block, work is done against the resistive forces exerted on the bullet by the block. This results in the reduction of the bullet's kinetic energy. The bullet has a speed v when it emerges from the block.

If the block exerts a resistive force F on the bullet and the thickness of the block is x then, the work done by the resistive force is given by,

$W=Fx$