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3 years ago

Using a cathode ray tube , what did Thomson confirm

Physics

2 answers:

Ira Lisetskai [31]3 years ago

8 0

Answer:

Its b

Explanation:

If ur on edgenuity!!

DiKsa [7]3 years ago

3 0

"J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged "soup." I looped this up, hoped it helped:)

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Please help ASAP.

Elden [556K]

Answer:

1st question c part

2nd question c part

8 0

3 years ago

MacGyver is riding on a skateboard and moving west of the velocity of 7 m/s. Macgyver has a mass of 92 kg and the skateboard has

ivann1987 [24]

Answer:

64.5

Explanation:

(m1 + m2) v initial = (m1 * v1 final) + (m2 * v2 final)

(92 + 8)(-7) = (92 x 2) + (8 x v2 final)

(100)(-7) = (184) + (8 x v2 final)

-700 = (184) + (8 x v2 final)

-516 = (8 x v2 final)

-516/8 = v2 final

-64.5 = v2 final

8 0

3 years ago

If you make multiple measurements of your height, you are likely to find that the results vary by nearly half an inch in either

Verdich [7]

Answer:

Height h= 1.7 m

Explanation:

Supposing we have to find height in meter.

1 feet = 0.3048 m

1 inch = 0.0254 m

Given that:

5 feet

= 5×0.3048

= 1.524 m

and 7 inch = 7×0.0254= 0.1778 m

Therefore total height of a man in meter

5 feet 7 inch = 1.5424+0.1778 =1.7 m

Height h= 1.7 m

3 0

4 years ago

A spring with spring constant of 26 N/m is stretched 0.22 m from its equilibrium position. How much work must be done to stretch

Evgen [1.6K]

Answer:

1.503 J

Explanation:

Work done in stretching a spring = 1/2ke²

W = 1/2ke²........................... Equation 1

Where W = work done, k = spring constant, e = extension.

Given: k = 26 N/m, e = (0.22+0.12), = 0.34 m.

Substitute into equation 1

W = 1/2(26)(0.34²)

W = 13(0.1156)

W = 1.503 J.

Hence the work done to stretch it an additional 0.12 m = 1.503 J

8 0

3 years ago

The half life of carbon-14 is 5730 years. How old is a bone if it presently contains 0.3125 g of carbon-14, but it was estimated

TiliK225 [7]

The age of the bone is 45840 years.

We'll begin by calculating the number of half-lives that has elapsed.

Amount remaining (N) = 0.3125 g

Initial amount (N₀) = 80 g

<h3>Number of half-lives (n) =? </h3>

N × 2ⁿ = N₀

0.3125 × 2ⁿ = 80

Divide both side by 0.3125

2ⁿ = 80 / 0.3125

2ⁿ = 256

2ⁿ = 2⁸

Thus, 8 half-lives has elapsed

Finally, we shall determine the age of the bone.

Half-life (t½) = 5730 years

Number of half-lives (n) = 8

t = n × t½

t = 8 × 5730

<h3>t = 45840 years </h3>

Therefore, the age of the bone is 45840 years.

Learn more on half-life: brainly.com/question/15900105

5 0

3 years ago