Answer:
(i) C=3Co
(ii) V=Vo/3
(iii) Decrease
Explanation:
(i) capacitance increase K times.
(ii) As charge remain constant so by using Q=CV
you will get potential decrease by K time.
(iii) Decrease due to induced electric field inside
dielectric material..
E=Eo-Eind
Explanation:
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Answer:
I have made a mistake in my answer
Answer:
yes; yes
Explanation:
Phases of the moon refers to the shapes of the moon due to the lit part of it visible from the Earth. On a new moon day, the moon comes between the sun and the earth such that the lit portion is not visible from the Earth. On a full moon day, the earth comes between the sun and the moon and the whole lit part is visible.
When one would view the earth from the moon, the earth would also be visible as going through the phases. The order would be reversed. Understand this with the following example, On a new moon day, the Earth would be visible completely lit from the moon. So it will be full Earth day on the moon. On a full moon day, the lit side of the Earth would be completely away and hence, from the moon, new earth would be there.
In a high-mass, main-sequence star energy produces at a faster rate by using carbon in a process that fuses hydrogen to helium.
A high mass star produces energy by the fusion of hydrogen to helium.
But in this process, oxygen, carbon and nitrogen act as catalyst to accelerate the energy generation process.
Energy burn very quickly and at a faster rate in a giant and high mass star than in a low mass star.
A star 10 x the mass of siun can live upto 20 million years whereas low mass start has greater lifespan than the present age of the universe.
If you need to learn more about star energy click here:
brainly.com/question/5552055
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(0.15 x g)/100 = 0.0147N. per cm. length.
<span>Torque short end = (0.0147 x 9) = 0.1323N/cm. </span>
<span>Torque long end = ((100 - 18)/2) x 0.0147 = 0.6027N/cm. </span>
<span>Difference = (0.6027 - 0.1323) = 0.4704N/cm. </span>
<span>(0.4704/3.2) = 0.147cm. from the 18cm. mark, = 17.853cm. from the 0 end of the stick.</span>
