What is the area, in square meters, of a right triangle with sides of length 8 meters, 15 meters, and 17 meters?
1 answer:
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Answer:
Step-by-step explanation:
The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.
The product of the gradients of perpendicular lines is -1.
Gradient of given line= 3.
(Gradient of line)(3)= -1
3m= -1
m=
subst. m= into the equation:
To find the value of c, substitute a coordinate.
When x=0, y=4,
Thus the equation of the line is .
Answer:
17
Step-by-step explanation:
Using the law of cosines in ΔABC
b² = a² + c² - (2ac cosB) ← substitute in values
= 25² + 28² - (2 × 25 × 28 × cos36.9°)
= 625 + 784 - 1400 cos36.9°
= 1409 - 1400 cos36.9° ( Take the square root of both sides )
b = ≈ 17 ( nearest whole number )