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babymother [125]
4 years ago
13

What is the area, in square meters, of a right triangle with sides of length 8 meters, 15 meters, and 17 meters?

Mathematics
1 answer:
cestrela7 [59]4 years ago
6 0

I believe it would be E. YW

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Sam bought a soda and a bag of chips for $3. If the soda cost $1.75, how much was the bag of chips?
Anarel [89]

Answer:

1.25

Step-by-step explanation:

The bag of chips is worth the same as the entire purchase minus the soda.

Therefore the chips are worth 3 - 1.75 = 1.25

3 0
4 years ago
Read 2 more answers
Miri counted her money and found that her 25 coins which were nickels, dimes, and quarters were worth $3.20. the number of dimes
Natasha_Volkova [10]
Nickels = x

dimes = x + 4

quarters = x

Value of coins:

nickel = 5 cents

dime = 10 cents

quarter = 25 cents

5x + 10(x + 4) + 25x = 3.20

5x + 10x + 40 + 25x = 320

40x = 320 - 40

40x = 280

x = 280/40

x = 7

There are 7 quarters, 7 nickels and 11 dimes.



4 0
3 years ago
A pet store 145 bags of beef flavored dog food and 263 bag of chesse flavored dog food how many bags of dog food where sold
Kazeer [188]

Answer:

408 bags of dog food

Step-by-step explanation:

The question asks for the total bags of dog food. Because they give you two existing values expressing how much dog food of each type there is, all you must do is add them together. 145 + 263 = 408

3 0
3 years ago
Write and solve a system of linear equations: The larger of two numbers is 18 more than 5 times the smaller. If 3 times the larg
marshall27 [118]

Answer:

8 and -2

Step-by-step explanation:

Let the numbers be l and s.

We have equations:

l = 5s + 18

3l + 4s = 16

Solve for s by substituting l into the second equation:

3(5s + 18) + 4s = 16

15s + 54 + 4s = 16

19s = 16 - 54

19s = -38

s = -38/19

s = -2

Find the value of l:

l = 5(-2) + 18

l = -10 + 18

l = 8

3 0
2 years ago
(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)
laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

4 0
4 years ago
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