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lbvjy [14]
3 years ago
5

Wendy and Mini earn $49 per week for delivering magazines. Wendy worked for x weeks and earned an additional total bonus of $18.

Mini worked for y weeks. Which expression shows the total money, in dollars, that Wendy and Mini earned for delivering magazin
A. 67x + 49y

B.49x − 18 + 49y

D. 49x + 18 + 49y

C. 49x + 67y
Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

The correct answer is D!! Please choose me brainliest!!!

Step-by-step explanation:

JulijaS [17]3 years ago
4 0
It's D, $49.00/wk for x weeks is 49x, plus $18.00 bonus is 49x+18, add the fact that Mini worked for y weeks, 49y. 
Read it slowly and out loud till you get it.

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For a function p(x), as |x|—> infinity then p(x)—> 3. Which of the following graphs could be p(x)?
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3 years ago
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



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