Answer:
m∠EGF = 65° and m∠CGF = 115°
Step-by-step explanation:
Given;
∠EFG = 50°
EF = FG
Solution,
In ΔEFG m∠EFG = 50° and EF = FG.
Since triangle is an isosceles triangle hence their base angles are always equal.
∴
Let the measure of ∠EGF be x.
∴ 
Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."
m∠EFG + m∠FEG + ∠EGF = 180

Hence
m∠EGF = 65°
Also 'The sum of angles that are formed on a straight line is equal to 180°."
m∠EGF + m∠CGF = 180°
65° + m∠CGF = 180°
m∠CGF = 180° - 65° = 115°
Hence m∠EGF = 65° m∠CGF = 115°
Work = (force) x (distance)
= (200 lb) x (10 ft) = 2,000 ft-lbs .
Answer:
x = 2/3
DF = 10
scale factor of ΔDEF to ΔXYX is 1:3
Step-by-step explanation:
DF corresponds to XZ and DE corresponds to XY so we can set up a proportion:
6x+6/30 = 8/24
simplify 8/24 to be 1/3
6x+6/30 = 1/3
cross-multiply:
3(6x+6) = 30
18x + 18 = 30
18x = 12
x = 12/18 or 2/3
Answer:
5x18
Step-by-step explanation:
5x6x3 and 5x18 equal 90