Triangle ABC is shown below with line DE passing through points D and E: Triangle ABC is shown with point D lying on side BC and
point E lying on side AC. Line DE is perpendicular to side AC. If triangle ABC is dilated about the center of the triangle to create triangle A'B'C', dilated line D'E' will be parallel to DE be perpendicular to DE lie on the same line as DE shift five units to the right
2 answers:
Answer:
It is given that, A Triangle ABC in which point D lying on side BC and point E lying on side AC.Line DE is perpendicular to side AC.
Now, triangle ABC is dilated about the center of the triangle to create triangle A'B'C' in such a way that D' lies on side B'C' and E' lies on side A'C'.
Both the line segment that is line segment DE and line segment D'E' will be parallel.
Option 1:Dilated line D'E' will be parallel to DE
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Answer:
C)
Step-by-step explanation:
Line of best fit (trendline) : a line through a scatter plot of data points that best expresses the relationship between those points.
All the given options for the line of best fit are linear equations.
Therefore, we can add the line of best fit to the graph (see attached), remembering to have roughly the same number of points above and below the line.
Linear equation:
(where is the slope and
is the y-intercept)
From inspection of the line of best fit, we can see that the y-intercept (where x = 0) is approximately 8. So this suggests that options C or D are the solution.
We can also see that the slope (gradient) of the line of best fit is approximately -0.5 (as the rate of change (y/x) is -1 unit of y for every +2 units of x).
Therefore, C is the solution, and the closet approximation to the line of best fit is
