$4 sin^{2} x-3=0 \\ 4 sin^{2} x=3 \\ sin^{2} x= \frac{3}{4} \\ sinx= \pm \sqrt{ \frac{3}{4} } \\ sinx= \frac{ \sqrt{3} }{2} \ or \ sinx=- \frac{ \sqrt{3} }{2} \\ x= \frac{ \pi }{3} , \ \frac{2 \pi }{3} , \ \frac{4 \pi }{3} , \ \frac{5 \pi }{3}$

5 0

3 years ago

AHHH HELPPP ME PLEASEE

Mamont248 [21]

Answer:

the third one is hard to see i think its 77 so the answer is 54.75

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Find the domain and range

victus00 [196]

Answer:

Domain) all x

Range) 1

Step-by-step explanation:

The domain is the x values and the range is the y values

In this case anything could be x, and y can only be 1

6 0

2 years ago