1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ahrayia [7]
3 years ago
7

Calculate the wavelength in centimeters of radar energy at a frequency of 10 GHz. What is the frequency in gigahertz of radar en

ergy at a wavelength of 25 cm
Physics
1 answer:
konstantin123 [22]3 years ago
7 0

Explanation:

(a) Frequency of radar energy, f = 10\ GHz =10^{10}\ Hz

The relation between frequency and wavelength is given by :

c=f\lambda

\lambda=\dfrac{c}{f}

\lambda=\dfrac{3\times 10^8}{10^{10}}

\lambda=0.03\ m

or

\lambda=3\ cm

(b) If wavelength, \lambda=25\ cm=0.25\ m

c=f\lambda

f=\dfrac{c}{\lambda}

f=\dfrac{3\times 10^8}{0.25}

f=1.2\times 10^9\ Hz

or

f = 1.2 GHz

Hence, this is the required solution.

You might be interested in
Can anybody help me with this Physics question! (DUE TOMORROW) (WILL MARK BRAINLIST)
Ymorist [56]
Do you need help with all of them
3 0
3 years ago
Read 2 more answers
The rebirth of science and learning during the fifteenth century is termed the
Pepsi [2]
The Renaissance, was the rebirth to science as well as many other advancements
5 0
4 years ago
If a player through a basketball to the target with an initial velocity of 17 m/s making an angle of 30 degrees with the horizon
Svetllana [295]

Answer:

The final position made with the vertical is 2.77 m.

Explanation:

Given;

initial velocity of the ball, V = 17 m/s

angle of projection, θ = 30⁰

time of motion, t = 1.3 s

The vertical component of the velocity is calculated as;

V_y = Vsin \theta\\\\V_y = 17 \times sin(30)\\\\V_y = 8.5 \ m/s

The final position made with the vertical (Yf) after 1.3 seconds is calculated as;

Y_f = V_yt  - \frac{1}{2}g t^2\\\\Y_f = (8.5 \times 1.3 ) - (\frac{1}{2} \times 9.8 \times 1.3^2)\\\\Y_f = 11.05 \ - \ 8.281\\\\Y_f = 2.77 \ m

Therefore, the final position made with the vertical is 2.77 m.

3 0
3 years ago
Illustrate a body of mass 5.0kg pulled by horizontal force F . if the body accelerates 2.0ms² and experience a frictional force
Natasha2012 [34]

Explanation:

a. Net force is mass times acceleration (Newton's second law).

∑F = ma

∑F = (5.0 kg) (2.0 m/s²)

∑F = 10 N

b. The net force is the sum of the individual forces.

10 N = F − 5 N

F = 15 N

c. Friction force here is mgμ.

mgμ = 5 N

(5.0 kg) (10 m/s) μ = 5 N

μ = 0.1

3 0
3 years ago
The Celsius temperature scale is based on which of the following
Lapatulllka [165]
Freezing.................
6 0
4 years ago
Other questions:
  • What is the mass number of an atom with 5 protons and 7 neutrons?
    5·2 answers
  • HELP NOW PLEASE The negatively charged particle that is released from the nucleus at high speeds is the _____.
    9·1 answer
  • ¿que es el calor latente
    5·1 answer
  • What type of lever is shown below?
    15·1 answer
  • What is the force of gravity between a 500kg bal and a 100,000kg basket 5m apart?
    7·2 answers
  • A charge -353e is uniformly distributed along a circular arc of radius 5.30 cm, which subtends an angle of 48°. What is the line
    6·1 answer
  • Based on the graph below, what prediction can we make about the acceleration when the force is 0 newtons? A. It will be 0 meters
    15·2 answers
  • A centripetal force of 250 N is exerted on a 2.2 kg discus as it rotates uniformly in a horizontal circle of radius 0.85 m. Calc
    8·1 answer
  • 1. What does the term monecious mean?
    13·1 answer
  • The positions of four objects as a function of time are shown
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!