Answer:
 KE₂ = 6000 J
Explanation:
Given that
Potential energy at top U₁= 7000 J
Potential energy at bottom U₂= 1000 J
The kinetic energy at top ,KE₁= 0 J
Lets take kinetic energy at bottom level =  KE₂
Now from energy conservation
 U₁+ KE₁= U₂+ KE₂
Now by putting the values
 U₁+ KE₁= U₂+ KE₂
 7000+ 0 = 1000+ KE₂
 KE₂ = 7000 - 1000 J
 KE₂ = 6000 J
Therefore the kinetic energy at bottom is 6000 J.
 
        
             
        
        
        
Answer:
20 km/h
Explanation:
45 km ÷ 2.25 hours (15 mins is 0.25 hours)
= 20
20 km/h
 
        
             
        
        
        
Answer:
Answer for the question is given in the attachment.
Explanation:
 
        
             
        
        
        
Answer:
The answer to the question is 
The roller coaster will reach point B with a speed of 14.72 m/s
Explanation:
Considering both kinetic energy KE = 1/2×m×v² and potential energy PE = m×g×h
Where m = mass 
g = acceleration due to gravity = 9.81 m/s²
h = starting height of the roller coaster
we have the given variables
h₁ = 36 m, 
h₂ = 13 m, 
h₃ = 30 m
v₁ = 1.00 m/s
Total energy at point 1 = 0.5·m·v₁² + m·g·h₁
 = 0.5 m×1² + m×9.81×36
=353.66·m
Total energy at point 2 = 0.5·m·v₂² + m·g·h₂
= 0.5×m×v₂² + 9.81 × 13 × m = 0.5·m·v₂² + 127.53·m
The total energy at 1 and 2 are not equal due to the frictional force which must be considered
Total energy at point 2 = Total energy at point 1 + work done against friction
Friction work = F×d×cosθ = ( × mg)×60×cos 180 = -117.72m
 × mg)×60×cos 180 = -117.72m
0.5·m·v₂² + 127.53·m = 353.66·m -117.72m
0.5·m·v₂² = 108.41×m
v₂² = 216.82
v₂  =  14.72 m/s
The roller coaster will reach point B with a speed of 14.72 m/s