Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
5
Step-by-step explanation:
Answer:
The angle that the line makes with x-axis of of 64.3º.
Step-by-step explanation:
Equation of a line, and angle with the x axis:
The equation of a line has the following format:

In which m is the slope.
The angle that the line makes with the x axis is given by the angle which has tangent m, that is,
.
In this question:
We have that
. So

The angle that the line makes with x-axis of of 64.3º.
Answer:
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Step-by-step explanation:
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