Answer with step-by-step explanation:
The distance between Rockville and San Jose is 2407.2. Since there are 63360 inches in a mile, we divide it by 2, which is 31680. We multiply 2407.2 by 31680, and get 76260096.
25 is about 3.32% of 752.
Answer: Correct critical value = 2.2622
Step-by-step explanation:
Confidence interval for population mean when population standard deviation is unknown:
, where
= sample mean, n= sample size, s= sample standard deviation,
= two-tailed t value.
As per given: n= 10
degree of freedom : df = n-1=9

Critical t-value : 
So, the 95 percent confidence interval estimate for the mean :

The 95 percent confidence interval estimate for the mean:(190.14, 295.06)
2/3
Divide the numerator and denominator by their gcd which is 5