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3 years ago

PLEASE HELP [99 POINTS] ONE QUESTION

Mathematics

2 answers:

Ugo [173]3 years ago

5 0

B.

Bread baked at 325 F has an average density of 0.42 g/cm^3.

As the temperature increases, the density decreases.

____ [38]3 years ago

4 0

The answer is B. "Bread baked at 325 °F has an average density of 0.42 g/cm³. As the temperature increases, the density decreases."

If you closely observe the table, you can see that the density starts at 0.42 and as the temperature increases, the density decreases, with the final density being 0.26 g/cm³.

Options C and D are invalid because the table only gives information about the temperature and the density, not the amount of time taken for the bread to bake.

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Write the expression 14(x+8) one other way.

Taya2010 [7]

14x+112
Distributive property

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3 years ago

Lf a+b=10 ,ab=21 then a^3+b^3=

Goshia [24]

Answer:

370

Step-by-step explanation:

a=3 or 7

b=7 or 3

3³+7³=370

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3 years ago

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Find the mean, meadian, mode and range for each set of data 6, 9, 2, 4, 3, 6, 5

Helga [31]

Mean: Add up the numbers and divide the sum by the number of values in the set.

6 + 9 + 2 + 4 + 3 + 6 + 5 = 35

35 / 7 = 5

Median: Sort the set from the smallest value to the largest value and select the number in the middle. If the count of the set if even, then select the two middle values and take their mean average.

2, 3, 4, 5, 6, 6, 9

So, the median average is 5.

Mode: What number appears the most frequently?

The mode of the set is 6 because it appears twice.

Range: Sort the set by ascending order and take the smallest value and subtract that from the largest value in the set.

9 - 2 = 7

The range is 7.

6 0

2 years ago

Read 2 more answers

Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt

-Dominant- [34]

Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is <u>tested if it does not outlast by more than 2 hours</u>, that is, the subtraction is not more than 2:

$H_0: \mu_B - mu_A \leq 2$

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

$H_1: \mu_B - \mu_A > 2$

The sample means are: $\mu_A = 8.65, \mu_B = 11.23$

The standard deviations for the samples are $s_A = s_B = 0.67$

Hence, the standard errors are:

$s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934$

The distribution of the difference has <u>mean and standard deviation</u> given by:

$\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58$

$s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 2$ is the value tested at the hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{2.58 - 2}{0.2735}$

$t = 2.12$

The critical value for a <u>right-tailed test</u>, as we are testing if the subtraction is greater than a value, with a <u>0.05 significance level</u> and 12 + 12 - 2 = <u>22 df</u> is given by $t^{\ast} = 1.71$

Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0

3 years ago

If f={ (1,2),(3,5),(4,1)} and g= { (2,3), (5,1),(1,3)} , then (gof)=?

guapka [62]

<h3>Answer: Choice (b)</h3><h3>{ (1, 3), (3, 1), (4, 3) }</h3>

==================================================

Work Shown:

The notation "g o f" means g(f(x)). We have f(x) as the inner function that is computed first.

f(x) = { (1,2), (3,5), (4,1) }

The x coordinates of each point are: 1, 3, 4

The y coordinates are: 2, 5, 1

So the input x = 1 goes to y = 2 as the output. That output becomes the input of the g(x) function. Using x = 2 as the input for g, we see that 3 is the output. Check out the diagram below to see how each input goes into f, then goes into g to ultimately determine the x,y pairs. So far we've shown that x = 1 ultimately leads to y = 3.

Let's do another input: if x = 3 is plugged into f(x), then the output is 5 because of the point (3,5). Then x = 5 is plugged into g(x) to get x = 5 lead to y = 1. Ultimately x = 3 leads to y = 1 giving us (3,1) as another point.

Lastly, if x = 4 is plugged into f we get y = 1 as an output, which in turn is plugged into g to get 3 as the final output. The point (4,3) is the last ordered pair.

Again there's a lot to keep track of, so it helps to have a diagram as shown below.

4 0

3 years ago

Read 2 more answers