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hichkok12 [17]
3 years ago
13

Suppose you are taking 2 cars. Each car gets 24 miles per gallon. How many gallons of gas will you need in total for both cars i

f you will be driving 54 miles?
Mathematics
1 answer:
makkiz [27]3 years ago
7 0
54/24 = 2.25, which is more than 2, so it rounds up to 3. So, one car will need three gallons. Since there are two cars, six gallons will be needed. 
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I have a bag of 4 cotton candy lollipops 3 cherry 6 butterscotch and 1 orange what is the probability of randomly choosing a cot
lorasvet [3.4K]

Answer:

= 1/2

Step-by-step explanation:

From the question: 1 bag contains

4 cotton candy lollipops

3 cherry lollipops

6 butterscotch lollipops

1 orange lollipops

Total number of possible outcomes =

14

The probability of randomly choosing a cotton candy or orange lollipops is calculated as:

P(Cotton candy) + P(Orange)

= 4/14 + 3/14

= 7/14

= 1/2

4 0
3 years ago
9 meters higher than altitude X
aleksklad [387]
X+9 ? I'm not sure if that was the kind of answer you were looking for but that's what I got out of that.
7 0
3 years ago
The slope of (-3,5) (-3,1)
weqwewe [10]

Answer:

undefined

Step-by-step explanation:

The slope of two points is found by

m = (y2-y1)/(x2-x1)

    = (1-5)/ (-3 - -3)

   = -4/(-3+3)

  = -4/0

undefined

6 0
4 years ago
Read 2 more answers
A bakery used 475 pounds of apples to make 1000 apple tarts. each tart contains the same ammount of apples. how many pounds of a
Gennadij [26K]
475 ÷ 1000 = 0.475 pounds per apple tart
3 0
3 years ago
Find out the answers to this
meriva

Answer:

\tan \theta = - \frac{1}{5} = - 0.2

\cos \theta = 0.98

\sin \theta = - 0.196

Step-by-step explanation:

It is given that \cot \theta = - 5 and \theta is in the fourth quadrant.

So, only \cos \theta will have positive value and \sin \theta, \tan \theta will have negative value.

Now, \cot \theta = - 5

⇒ \tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5} (Answer)

We know, that \sec^{2} \theta - \tan^{2} \theta = 1

⇒ \sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019

{Since, \cos \theta is positive then \sec \theta will also be positive}

⇒ \cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98 (Answer)

We know, that \csc^{2} \theta - \cot^{2} \theta = 1

⇒ \csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099

{Since, \sin \theta is negative then \csc \theta will also be negative}

⇒ \sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196 (Answer)

4 0
3 years ago
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