Which expressions can be used to find the coordinates of the midpoint of PQ with endpoints P(3, –1) and Q(–7, –6)?
1 answer:
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Answer:
(a) 16 students failed for exactly two of the three reasons.
(b) 7 students failed because of poor attendance and not studying but not because of not turning in assignments.
(c) 14 students failed because of exactly one of the three reasons.
(d) 3 students failed because of poor attendance and not turning in assignments but not because of not studying.
Step-by-step explanation:
We are given that one semester in a chemistry class, 14 students failed due to poor attendance, 23 failed due to not studying, 15 failed because they did not turn in assignments, 9 failed because of poor attendance and not studying, 8 failed because of not studying and not turning in assignments, 5 failed because of poor attendance and not turning in assignments, and 2 failed because of all three of these reasons.
As shown in the diagram attached below, a Venn diagram represents the situation given in the question;
In the diagram below, 2 in represents purple color represents the number of students failed because of all three of these reasons.
7 represents the number of students who failed because of poor attendance and not studying but not due to not turning in assignments.
6 represents the number of students who failed because of not studying and not turning in assignments but not due to poor attendance.
3 represents the number of students who failed because of poor attendance and not turning in assignments but not due to not studying.
2 in red color represents the number of students who failed only due to poor attendance.
8 in red color represents the number of students who failed only due to not studying.
4 in red color represents the number of students who failed only due to not turning in assignments.
(a) The number of students who failed because of exactly two of the three reasons = 7 + 6 + 3 = 16 students.
(b) The number of students who failed because of poor attendance and not studying but not because of not turning in assignments = 9 - 2 = 7 students.
(c) The number of students who failed because of exactly one of the three reasons = 2 + 8 + 4 = 14 students.
(d) The number of students who failed because of poor attendance and not turning in assignments but not because of not studying = 5 - 2 = 3 students.
Answer:
x g(x + 2)-1 h(x)
-2 g(-2+2)-1 -1
-1 g(-1+2)-1 0
0 g(0+2)-1 1
1 g(1+2)-1 2
2 g(2+2)-1 3
Part A: 3
Part B: -1
Step-by-step explanation:
When you have questions like these all you have to do is plug in and solve.
For example I will do h(2) & h(-2) for reference.
<em><u>h(2):</u></em>
<em><u>h(-2):</u></em>