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Alexxandr [17]
3 years ago
5

A watt is equal to ____

Physics
2 answers:
alexira [117]3 years ago
7 0
One Joule per second.  It's the time rate at which energy is used or produced.  In the most basic units 
Bond [772]3 years ago
4 0
A watt is equal to 1 joule/second

hope this helps :)

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The membrane that surrounds a certain type of living cell has a surface area of 5.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A
kotykmax [81]

Answer:

2.1\times 10^{-12} c

Explanation:

We are given that

Surface area of membrane=5.3\times 10^{-9} m^2

Thickness of membrane=1.1\times 10^{-8} m

Assume that membrane behave like a parallel plate capacitor.

Dielectric constant=5.9

Potential difference between surfaces=85.9 mV

We have to find the charge resides on the outer surface of membrane.

Capacitance between parallel plate capacitor is given by

C=\frac{k\epsilon_0 A}{d}

Substitute the values then we get

Capacitance between parallel plate capacitor=\frac{5.9\times 8.85\times 10^{-12}\times 5.3\times 10^{-9}}{1.1\times 10^{-8}}

C=0.25\times 10^{-12}F

V=85.9 mV=85.9\times 10^{-3}

Q=CV

Q=0.25\times 10^{-12}\times 85.9\times 10^{3}=2.1\times 10^{-12} c

Hence, the charge resides on the outer surface=2.1\times 10^{-12} c

5 0
3 years ago
Read 2 more answers
A rigid beam with one end at the origin has a force, F = 7.1 i +-1.8 j +7.8 k N acting on it at a position r = 2.4 i +5.3 j +8.4
myrzilka [38]

Explanation:

A rigid beam with one end at the origin has a force, F = 7.1 i +-1.8 j +7.8 k N acting on it at a position r = 2.4 i +5.3 j +8.4 k m from its fixed pivot point at the origin, Determine the magnitude of the torque exerted by this force.

a.

81.38 Nm

b.

4579.39 Nm

c.

109.33 Nm

d.

None of the other answers is correct

e.

0.00 Nm

4 0
3 years ago
What would changing the frequency of a wave do to the wave?
nata0808 [166]
The data convincingly show that wave frequency does not affect wave speed. An increase in wave frequency caused a decrease in wavelength while the wave speed remained constant. The last three trials involved the same procedure with a different rope tension.
3 0
3 years ago
A 2530-kg test rocket is launched vertically from the launch pad. Its fuel (of negligible mass) provides a thrust force so that
gavmur [86]

Answer:

A = 1.4 m/s²

B = -0.10493 m/s³

a = 1.29507 m/s²

T = 28095.8271 N

T = 1.13198 W

Explanation:

t = Time taken

g = Acceleration due to gravity = 9.81 m/s²

The equation

v(t)=At+Bt^2

Differentiating with respect to time

\frac{dv}{dt}=\frac{d(At+Bt^2)}{dt}\\\Rightarrow 1.4=A+2Bt

At t = 0

1.4=A

Hence, A = 1.4 m/s²

B=\frac{v-At}{t^2}\\\Rightarrow B=\frac{2.18-1.4\times 1.8}{1.8^2}\\\Rightarrow B=-0.10493\ m/s^3

B = -0.10493 m/s³

At t = 5 seconds

a=1.4+2\times -0.010493\times 5=1.29507\ m/s^2

a = 1.29507 m/s²

T=m(a+g)\\\Rightarrow T=2530(1.29507+9.81)\\\Rightarrow T=28095.8271\ N

T = 28095.8271 N

Weight of rocket

W=2530\times 9.81=24819.9\ N

\frac{T}{W}=\frac{28095.8271}{24819.9}\\\Rightarrow \frac{T}{W}=1.13198\\\Rightarrow T=1.13198W

T = 1.13198 W

3 0
4 years ago
How long does it take a car travelling at 80 m/s to decelerate to 18 m/s with an acceleration rate of -16m/s?
sertanlavr [38]
  • initial velocity=u=80m/s
  • Final velocity=v=18m/s
  • Acceleration=a=-16m/s^2
  • Time=t

We know

\boxed{\sf a=\dfrac{v-u}{t}}

\\ \sf\longmapsto t=\dfrac{v-u}{a}

\\ \sf\longmapsto t=\dfrac{18-80}{-16}

\\ \sf\longmapsto t=\dfrac{-62}{16}

\\ \sf\longmapsto t=3.8s

4 0
3 years ago
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