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DIA [1.3K]
3 years ago
5

In 10 seconds a car accelerates 4/ms to 60m/s. how fast was the car going before it accelerated?

Physics
2 answers:
AnnyKZ [126]3 years ago
8 0

Answer:

<h2>4m /s.</h2>

Explanation:

Acceleration is defined as the change of velocity, that is, when the velocity increases or decreases, there's acceleration. When the velocity doesn't change, there's no acceleration or it's null.

So, in this case, the initial velocity of the accelerated period is 4m/s, and after the period is 60m/s. This means 4m/s represents the velocity before the acceleration and 60m/s represents the velocity after the acceleration.

Therefore, the right answer here is 4m/s.

SVETLANKA909090 [29]3 years ago
6 0
Well it seems like this problem gives you what you need.  You said the car was going 4m/s and then accelerated to 60m/s... so 4m/s would be your answer for the initial velocity
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3 years ago
Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 403 km above the earth’s sur
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Answer:

v_A=7667m/s\\\\v_B=7487m/s

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

F_g=\frac{GMm}{R^{2} }

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

F_c=m\frac{v^{2}}{R}

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So R_A=6774km=6.774*10^6m and R_B=7103km=7.103*10^6m (Since R_{earth}=6371km). Then, we get:

v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).

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3 years ago
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Step two is to form your hypothesis: “A basketball will bounce higher if there is more air it”

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Here the independent variable is how much air is in the basketball (what you want to change) and the dependent variable is how high the b-ball will bounce (what will change as a result of the independent variable)

Step four is to record all of your results and step five is to analyze that data. Does your data support your hypothesis? Why or why not?

You should only test one variable at a time because it is easier to tell why the results are how they are; you only have one cause.

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3 years ago
Read 2 more answers
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