Question

The length of a triangle is 3/2 units grater than its width. if the width is w whitch expression gives the perimiter of the rectangle in terms of its width

Answer 1

Given the width of a rectangle = w

And the length given is $\frac{3}{2}$ units greater than its width.

So the length of the triangle = $(w+\frac{3}{2})$

We know that the perimeter of the rectangle is $2(length +width)$

So by plugging in the values of length and width in terms of w, we will get,

Perimeter = $2((w+\frac{3}{2})+w)$

= $2(w+\frac{3}{2}+w)$

We will add the like terms now.

$2(2w+\frac{3}{2} )$

Now we have to expand this expression by distributing 2, We will get,

$4w+(\frac{3}{2} )(2)$

$4w+\frac{(3)(2)}{2}$

$4w+\frac{6}{2}$

$4w+3$

So we have got the required perimeter of the rectangle in terms of w.

The perimeter is (4w+3) units.