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2 years ago

Which set does not contain –3?

Mathematics

1 answer:

STALIN [3.7K]2 years ago

8 0

Set? Are you missing part of the question

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Evaluate the expression. 5^2. what is the value of the expression?

vovangra [49]

Answer:

Step-by-step explanation:

Any numbers to the 2nd powered are always squared. Whenever you are given an exponent, the base is the number that you multiply, and the power is one more than how many times you multiply the base number together. In this case, you multiply five by itself once to get 25 as your answer.

7 0

3 years ago

Read 2 more answers

SOMEONE PLS HELP QUICK WILL GIVE BRAiNLIEST

skad [1K]

Answer:

1. x^2-9x+18

2. 2x^2-4x-16

3. 3x^2-19x-14

4. 6x^2 +14x + 8

Step-by-step explanation:

1. (x-3)(x-6)

x^2 - 6x - 3x +18 = x^2-9x+18

2. (2x+4)(x-4)

2x^2-8x+4x-16 = 2x^2-4x-16

3. (x-7)(3x+2)

3x^2+2x-21x-14 = 3x^2-19x-14

4. (3x+4)(2x+2)

6x^2+6x+8x+8 = 6x^2 +14x + 8

6 0

3 years ago

On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John

insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

$H_{max}=\frac{v^2}{2g}$

$H_{max} = \frac{(48)^2}{2 \times 12}$

= 96 ft

b). Time he can stay in the air before hitting the ground is

$T=\frac{2v}{g}$

$T=\frac{2 \times 48}{12}$

= 8 seconds

c). Considering upward motion as positive direction.

v = u + at

We find the time taken to reach the maximum height by taking v = 0.

v = u + at

0 = 16 + (12) t

$t=\frac{16}{12}$

$=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t = $=\frac{4}{3} \ s$ , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$ feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0

3 years ago

What is the range of the graph

Montano1993 [528]

Answer:

Range: all real numbers greater than or equal to 2

Step-by-step explanation:

The range is the possible numbers that the output can take

Y can be any number greater than or equal to 2

Range: all real numbers greater than or equal to 2

8 0

3 years ago

If alpha beta are the roots of the equation

Vikki [24]

Answer:

Step-by-step explanation:

Hello, I believe that we can consider a different from 0.

By definition of the roots we can write.

$ax^2+bx+c=a(x-\alpha)(x-\beta)=a(x^2-(\alpha + \beta)x+\alpha \cdot \beta)\\\\\text{So we can say that:}\\\\\alpha + \beta = \dfrac{-b}{a}\\\\\alpha \cdot \beta=\dfrac{c}{a}\\\\\text{So the expected quadratic equation is}\\\\(x+\dfrac{b}{a})(x-\dfrac{c}{a})=0\\\\ \Large \boxed{\sf \bf \ (ax+b)(ax-c)=0 \ }$

Thank you

8 0

3 years ago