2(b-5)+3(b-2)=8+7(b-4)
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1 answer:
<span>2(b-5)+3(b-2)=8+7(b-4)
We simplify the equation to the form, which is simple to understand
<span>2(b-5)+3(b-2)=8+7(b-4)
Reorder the terms in parentheses
<span>+(+2b-10)+3*(b-2)=8+7*(b-4)
Remove unnecessary parentheses
<span>+2b-10+3+*(+b-2+)=+8+7+*(+b-4+)
Reorder the terms in parentheses
<span>+2b-10+(+3b-6)=8+7*(b-4)
Remove unnecessary parentheses
<span>+2b-10+3b-6=+8+7+*(+b-4+)
Reorder the terms in parentheses
<span>+2b-10+3b-6=8+(+7b-28)
Remove unnecessary parentheses
<span>+2b-10+3b-6=+8+7b-28
We move all terms containing b to the left and all other terms to the right.
<span>+2b+3b-7b=+8-28+10+6
We simplify left and right side of the equation.
<span><span>-2b=-4
</span>We divide both sides of the equation by -2 to get b.
<span>b=2</span></span></span></span></span></span></span></span></span></span></span>
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