Question

2(b-5)+3(b-2)=8+7(b-4) Show work ASAP please

Answer 1

2(b-5)+3(b-2)=8+7(b-4)

We simplify the equation to the form, which is simple to understand
2(b-5)+3(b-2)=8+7(b-4)

Reorder the terms in parentheses
+(+2b-10)+3*(b-2)=8+7*(b-4)

Remove unnecessary parentheses
+2b-10+3+*(+b-2+)=+8+7+*(+b-4+)

Reorder the terms in parentheses
+2b-10+(+3b-6)=8+7*(b-4)

Remove unnecessary parentheses
+2b-10+3b-6=+8+7+*(+b-4+)

Reorder the terms in parentheses
+2b-10+3b-6=8+(+7b-28)

Remove unnecessary parentheses
+2b-10+3b-6=+8+7b-28

We move all terms containing b to the left and all other terms to the right.
+2b+3b-7b=+8-28+10+6

We simplify left and right side of the equation.
-2b=-4

We divide both sides of the equation by -2 to get b.
b=2