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irina1246 [14]
3 years ago
15

What do we call the bright, sphere-shaped region of stars that lie within a few thousand light-years of the center of the milky

way galaxy?
Physics
1 answer:
blagie [28]3 years ago
3 0
It is the galaxy’s bulge.
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Which of the following is not a source of light? *<br> a) sun<br> b) star<br> c) mirror<br> d)cfl
Vladimir [108]

I think that would be c) mirror because mirrors reflects light and can't create it.

5 0
3 years ago
A boy threw a ball upward and it took 3 sec to reach the highest point. Determine the initial velocity of the ball.
makkiz [27]

Answer:

V initial = 29.4 m.s²

Explanation:

( Using the laws of motion)

V final = V initial + Acceleration × time

0 = V initial + ( -9.8)(3)

29.4 = V initial

* I took upward as positive that's why I substituted -9.8 *

* for V final we know that at maximum height the ball is not moving thats why is = 0 *

6 0
2 years ago
You want to lift a heavy box with a mass L = 56.0 kg using the two-ideal pulley system as shown. With what minimum force do you
Olin [163]

The minimum force required to lift the box at constant velocity is determined as 274.4 N.

<h3>Minimum force required</h3>

The minimum force required to lift the box at constant velocity is the tension in one of the pulleys, and the magnitude is calculated as follows;

2T = mg

where;

  • m is mass of the box
  • T is the minimum force required

2T = mg

T = mg/2

T = (56 x 9.8)/2

T = 274.4 N

Learn more about minimum force here: https://brainly.in/question/47873510

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3 0
3 years ago
A law enforcement officer in an intergalactic "police car" turns on a red flashing light and sees it generate a flash every 1.2
butalik [34]

Answer:

The velocity of the police car relative to earth is v_{rel} = 2.51\times 10^{8} m/s

Given:

time for flash generation of the inter galactic police car, t = 1.2 s

time between flashes as measured from earth, t' = 2.2 s

Solution:

Utilising Einstein's equation for time dilation to calculate the velocity of the police car, the equation is given by:

t' = \frac{t}{\sqrt {1 - \frac{v^{2}}{c^{2}}}}                                (1)

where, c = speed of light in vacuum = c = 3\times 10^{8}

re arranging eqn (1) for velocity, v:

v_{rel} = c\times \sqrt {1 - (\frac{t}{t'})^{2}}                               (2)

Now, from eqn (2)

v_{rel} = 3\times 10^{8}( \sqrt {1 - (\frac{1.2}{2.2})^{2}})

v_{rel} = 3\times 10^{8}\times 0.838

v_{rel} = 2.51\times 10^{8} m/s

3 0
3 years ago
Which characteristics define a liquid?
Artemon [7]
Undefined shape, particles or atoms are loose, wet
3 0
3 years ago
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