Moment of inertia for one rod is expressed as:
<span>
I(1)= I(end) + md^2 = (1\12)mL^2+m(L/2√2)^2=(5/24)mL^2
</span><span>
Therefore, for two rods:
</span><span>
I2 = 2I1 = (5/12)mL^2
</span><span>
For the moment of inertia at the pivot point,
</span><span>
I=I2+2md^2=(5/12)mL^2+2(m(L/2√2)^2)=(2/3)mL^2
</span><span>
Substituting the equations above to the equation for frequency:
</span><span>
f=(1/2π)√(2mgd/I)=(1/4π)√(6g/√2L)</span>
Answer:
The resulting magnetic force on the wire is -1.2kN
Explanation:
The magnetic force on a current carrying wire of length 'L' with current 'I' in a magnetic field B is
F = I (L*B)
Finding (L * B) , where L = (2, 0, 0)m , B = (30, -40, 0)
L x B =
= (0, 0, -80)
we can now solve
F = I (L x B) = I (-80)
F = -1200 kmN
F = -1200 kN * 10⁻³
F = -1.2kN
Gravitational potential energy i think
D. 128.25 because force=mass x acceleration
Answer:
3. western slope
Explanation:
If we investigate the physical features (such as natural and artificial features) of the Sierra Nevada Mountains located at the California's central valley eastern part, the western slope has the highest value of the precipitation level yearly. This is due to the location of the slope and the relevant conditions such as temperature and humidity.