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bogdanovich [222]
3 years ago
5

describe the charge, mass and the location of each subatomic particle and the role each plays in determining the properties of a

n atom
Physics
1 answer:
Harrizon [31]3 years ago
6 0

Explanation :

An atom is a smallest particle of matter. An atom consists of protons, neutrons and electrons. These are three subatomic particles.

Protons are positively charged species while neutrons are negatively charged species. Electrons revolves around an atom.

Charge :

The charge of an electron is negative or -1.6\times 10^{-19} \ C

The charge of proton is +e or   1.6\times 10^{-19} \ C

Neutron has no charge.

Mass :

Atomic mass of electron is 9.1\times10^{-31}\ Kg

Atomic mass of proton is 1.67\times10^{-27}\ Kg

Atomic mass of neutron is 1.67\times10^{-27}\ Kg

Both protons and neutrons are located inside the nucleus at the center.

Charge, atomic mass and location determines the properties of an atom. Atomic mass tells about the number of protons and neutrons inside an atom.  Electric charge tells us the number of electrons gain or lost.

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We want to multiply the force by 16, so we need to
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The distance should be changed to  1/4  of what it is now.

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Please awnser and show the ways​
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Answer:

Answers in solutions.

Explanation:

<u>Question 6:</u>

The density of gold is 19.3 g/cm³

The density of silver is 10.5 g/cm³

  • The density of the substance in Crown A;

Density = mass ÷ volume = \frac{1930}{100} = 19.3 g/cm³

Since the density of gold, given, is 19.3 g/cm³ and the density of the substance in Crown A has a density of 19.3 g/cm³ , then that substance must be gold.

  • The density of the substance in Crown B;

Density = mass ÷ volume = 1930 ÷ 184 = 10.48913043  g/cm³ ≈ 10.5 g/cm³  (answer rounded up to one decimal place)

Since the density of the substance in Crown B is approximately equal to 10.5 g/cm³ , then that substance is Silver.

  • The density of substance in Crown C;

Density = mass ÷ volume = 1930g ÷ 150cm³ = 12.86666667 ≈ 12.9 cm³ (answer rounded up to one decimal place)

<h3><u>The density of the mixture:</u></h3><h3 />

For 2 cm³ of the mixture, its mass equal 19.3 g + 10.5 g = 29.8 g

∴ for 1 cm³ of the mixture, its mass equal to \frac{29.8}{2} = 14.9 g

Hence the density of the mixture = 14.9 g/cm³ and is not equal to the density of the substance in Crown C.

* Crown C is not made up of a mixture of gold and silver.

<u>Question 7:</u>

<u />

  • An empty masuring cylinder has a mass of 500 g.
  • Water is poured into measuring cylinder until the liquid level is at the 100 cm³ mark.
  • The total mass is now 850 g

The mass of water that occupied the 100 cm³ space of the container = total mass - mass of the empty container = 850 g - 500 g = 350 g

Density of the liquid (water) poured into the container = mass ÷  volume = 350 g ÷ 100 cm³ = 3.5g/cm³

<u>Question 8:</u>

<u />

A tank filled with water has a volume of 0.02 m³

(a) 1 liter = 0.001 m³

How many liters? = 0.02 m³ ?

Cross multiplying gives:

\frac{0.02 * 1}{0.001} =  20 liters

(b) 1 m³ = 1,000,000 cm³

0.02 m³ = how many cm³ ?

Cross-multiplying gives;

\frac{0.02 * 1,000,000}{1} = 20,000 cm³

(c) 1 cm³ = 1 ml

∴ 0.02 m³ of the water = 20,000 cm³ = 20,000 ml

<u>Question 9:</u>

<u />

Caliper (a) measurement = 3.2 cm

Caliper (b) measurement = 3 cm

<u>Question 10:</u>

<u />

  • A stone is gently and completely immersed in a liquid of density 1.0 g/cm³
  • in a displacement can
  • The mass of liquid which overflow is 20 g

The mass of the liquid which overflow = mass of the stone = 20 g

1 gram of the liquid occupies 1 cm³ of space.

20 g of the liquid will occupy; \frac{20 * 1}{1} = 20 cm³

(a) Since the volume of the water displaced is equal to the volume of the stone.

∴ The volume of the stone = 20 cm³

(b) Mass = density ×  volume

Density of the stone = 5.0 g/cm³

Volume of the stone = 20 cm³

Mass of the stone = 5 g/cm³ × 20 cm³ = 100 g

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3 years ago
một ô tô chuyển động nhanh dần đều.Sau 10s vận tốc của xe tăng từ 2m/s lên 6m/s.Tính gia tốc của ô tô
Serjik [45]

Answer:

áp dụng công thức í, mình thấy câu này có rắc rối gì đâu

8 0
3 years ago
What is the coefficient of friction between the skates and the ice?
natta225 [31]

The coefficient of friction is 0.051

Explanation:

The motion of the skater is a uniformly accelerated motion, therefore we can use the following suvat equation:

v^2 - u^2 = 2as

where:

v = 0 is the final velocity of the skater (he comes to a stop)

u = 10.0 m/s is his initial velocity

a is the acceleration

s=1.0\cdot 10^2 m = 100 m is the distance he travels before stopping

Solving for a, we find the acceleration of the skater:

a=\frac{v^2-u^2}{2s}=\frac{0-10.0^2}{2(100)}=-0.5 m/s^2

We also know that the net force acting on the skater is the force of friction, therefore we can write (Newton's second law of motion):

F= ma = -\mu mg

where

-\mu mg is the force of friction

m is the mass of the skater

\mu is the coefficient of friction

a=-0.5 m/s^2 is the acceleration

g=9.8 m/s^2 is the acceleration of gravity

Solving for \mu, we find the coefficient of friction:

\mu = -\frac{a}{g}=-\frac{-0.5}{9.8}=0.051

Learn more about friction:

brainly.com/question/6217246

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#LearnwithBrainly

8 0
3 years ago
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