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3 years ago

A 1,000 kg ball traveling at 5 m/s would have kinetic energy

Physics

1 answer:

MatroZZZ [7]3 years ago

6 0

Answer:

12500 J = 12.5 kJ

Explanation:

Kinetic energy is the energy possessed by a moving object solely due to its motion.

You can get the K.E. of an object using the equation,

K.E. = (1/2)mv²

So you get, for ball

K.E. = (1/2)×1000×5² = 12500 J = 12.5 kJ

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A uniform rod rotates in a horizontal plane about a vertical axis through one end. The rod is 3.46 m long, weighs 12.8 N, and ro

Mkey [24]

Answer:

a. Rotational inertia: 5.21kgm²

b. Magnitude of it's angular momentum: 123.32kgm²/s

Explanation:

Length of the rod = 3.46m

Weight of the rod = 12.8 N

Angular velocity of the rod= 226 rev/min

a. Rotational Inertia (I) about its axis

The formula for rotational inertia =

I = (1/12×m×L²) + m × ( L ÷ 2)²

Where L = length of the rod

m = mass of the rod

Mass of the rod is calculated by dividing the weight of the rod with the acceleration due to gravity.

Acceleration due to gravity = 9.81m/s²

Mass of the rod = 12.8N/ 9.81m/s²

Mass of the rod = 1.305kg

Rotational Inertia =

(1/12× 1.305 × 3.46²)+ 1.305 ( 3.46÷2)²

Rotational Inertia = 1.3019115 + 3.9057345

Rotational Inertia = 5.207646kgm²

Approximately = 5.21kgm²

b. The magnitude of the rod's angular momentum about the rotational axis is calculated as

Rotational Inertia about its axis × angular speed of the rod.

Angular speed of the rod is calculated as= (Angular velocity of the rod × 2π)/60

= (226×2π) /60

= 23.67 rad/s

Rotational Inertia = 5.21kgm²

The magnitude of the rod's angular momentum about the rotational axis

= 5.21kgm²× 23.67 rad/s

= 123.3207kgm²/s

Approximately = 123.32kgm²/s

7 0

3 years ago

A hard rubber ball on a string is being used as a pendulum. When you first look at the pendulum, the ball is being held to one s

Wittaler [7]

Answer:

<h2>Total thermal energy for all air molecules is 59.54 J</h2>

Explanation:

As we know that the ball comes to rest finally so here we can say that

initial total potential energy of the ball is transferred to the air molecules

So here we have

$E_{th} = mgh$

$E_{th} = (6.2 kg)(9.8 m/s^2)(0.98 m)$

So here we have

$E_{th} = 59.54 J$

So all the gravitational potential energy of the ball will convert into thermal energy of air molecules which is equal to 59.54 J

4 0

4 years ago

The momentum of an object is determined to be 7.2 X 10-3 kg m/s. Express this quantity as provider or use any equivalent unit.

olasank [31]

There could be more than just one answer, since kilograms can be converted to grams, to miligrams, etc.

$7.2\frac{g.m}{s}$

$7200\frac{mg.m}{s}$

Why?

Let's remember some conversion factors to work with kilograms (kg)

$1kg=1000g=1x10^{3}g \\1kg=1,000,000mg=1x10^{6}mg \\1g=1000mg=1x10^{3}mg$

So, we are given the momentum:

$momentum=7.2x10^{-3} \frac{kg.m}{s}$

We can rewrite the units of the momentum (equivalent) as follow:

$momentum=7.2x10^{-3}kg \frac{m}{s}=7.2x10^{3} x10^{-3}g\frac{m}{s}=7.2\frac{g.m}{s}$

and

$momentum=7.2x10^{-3}kg \frac{m}{s}=7.2x10^{3} x10^{6}mg\frac{m}{s}=7.2x10^{3}\frac{mg.m}{s}$

Note: There could be more equivalent units for the momentum, in example, we could work with equivalent units for meters (distance) and seconds (time).

Have a nice day!

8 0

3 years ago

Read 2 more answers

If the archerfish spits its water 60. degrees from the horizontal aiming at an insect 2.0 m above the surface of the water, how

MA_775_DIABLO [31]

<span>Using the kinematic equations below, we can calculate the initial velocity required. Angle of projectile = 60 degrees Acceleration due to gravity (Ay) = -10 m/s^2 (negative because downward) Height of projectile (Dy) = 2m Vfy^2=Voy^2 +2*Ay*Dy Vfy = 0 m/s because the vertical velocity slows to zero at the height of its trajection. So... 0 = Voy^2 + 2(-10)(2) 0 = Voy^2 - 40 40 = Voy^2 Sqrt40 = Voy 6.32 m/s = Voy THIS IS NOT THE ANSWER. THIS IS JUST THE INITIAL VELOCITY IN THE Y DIRECTION. Using trigonometry, Tan 60 = Voy/Vox. Tan 60 = 6.32/Vox. Vox*Tan 60 = Vox Vox = 10.95 m/s. Now, using Vox = 10.95 and Voy = 6.32, we can use pythagorean theorem to find the total Vo. A^2 +B^2 = C^2 10.95^2 + 6.32^2 = C^2 Solving for C = 12.64 m/s This is the velocity required to hit the surface. You can also calculate a bunch of other stuff now using the other kinematic equations. V = 12.64 m/s</span>

5 0

3 years ago

Read 2 more answers

How many newtons of force are represented by the following amount: 3 kg.m/sec2

alekssr [168]

I believe the answer is 3 Newtons!

5 0

3 years ago