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Nat2105 [25]
3 years ago
8

The model shows how solar-powered electric cars indirectly use energy from the Sun. Describe the energy transformations that you

see.
Physics
2 answers:
DiKsa [7]3 years ago
3 0
Solar energy duh lol or thermal
Vedmedyk [2.9K]3 years ago
3 0

Answer:

Radiant energy from the Sun is converted into electrical energy. This electrical energy is then converted into chemical energy that is stored in the battery. This chemical energy is then converted into electrical energy that is used to drive the motor of the electric car, which converts it into mechanical energy. Mechanical energy makes the car move.

<em>short: radiant energy-->electrical-->chemical-->electrical-->mechanical</em>

Explanation:

<h3>this was the actual answer, so re word.</h3>

<u>.-*.-*hope this helps!!! pls rate 5 stars*-.*-.</u>

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Car headlights use concave mirrors. There's a concave mirror in the back of the headlight socket, and the actual light bulb is p
katen-ka-za [31]

Answer:

At the focus

Explanation:

In car head lights concave mirrors are used. The light bulbs in these headlights are place along the principal axis  as shown in the figure. On this Principal axis light bulbs are place at the Focus to get maximum brightness. As from the figure we can conclude that light rays coming from infinity converse at focus thus, giving maximum brightness.

7 0
3 years ago
A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin
gogolik [260]

Answer:

a) 23 m/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

       p_{o} = p_{f}  (1)

  • The initial momentum p₀, can be written as follows:

       p_{o} =  m_{1}  * v_{1o} + m_{2}* v_{2o} =   6.0 kg * 5.0 m/s + 2.0 kg * v_{2o}  (2)

  • The final momentum pf, can be written as follows:

        p_{f} = (m_{1} + m_{2} )* v_{f}  = 8.0 kg* (-2.0 m/s)  (3)

  • Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

       v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg}  = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s  (4)

  • This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.
6 0
3 years ago
A car accelerates uniformly in a straight line
Alinara [238K]

Recall that

{v_f}^2={v_i}^2=2a\Delta x

The car starts from rest, so v_i=0, and we get

{v_f}^2=2\left(2.8\dfrac{\rm m}{\mathrm s^2}\right)(69\,\mathrm m)\implies v_f\approx19.66\dfrac{\rm m}{\rm s}

4 0
3 years ago
A na+ ion moves from inside a cell, where the electric potential is -72 mv, to outside the cell, where the potential is 0 v. wha
Vlada [557]
The change in electric potential energy of the ion is equal to the charge multiplied by the voltage difference:
\Delta U = q \Delta V = q (V_f - V_i)
where the charge q of the na+ ion is equal to one positive charge, so it's equal to the proton charge: q=1.6 \cdot 10^{-19} C, and Vf and Vi are the final and initial voltages.

Substituting the numbers, we find:
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7 0
3 years ago
Read 2 more answers
A frame hanging on a wall is held by two cables. The tension in each cable is 30 N, and the cables make an angle of 45° with the
Vesna [10]

Answer:

(D) 42.4N

Explanation:

Since the frame is at rest, the net force acting on it must be 0. There are three forces acting on it: the gravity and the opposing forces of the two cables.

Since the gravity is a vertical force, we are only interested in the vertical components of the remaining forces. The net force equation is

F_net = 0 = F_g -2 * F_y

The vertical force of one cable (using the information in the drawing) is:

F_y = 30N * sin 45 deg = 21.21N

Now the weight can be determined:

0 = F_g - 2 * F_y

F_g= 2 * F_y = 2 * 21.21N = 42.4N

The weight of the frame is about 42.4N.


6 0
3 years ago
Read 2 more answers
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