Answer:
Vector u has u_x = (5 - 15) = -10, and u_y = -4 - 22 = -26, and its component form would be u = -10i - 26j.
If vector v is in the opposite direction: 10i + 26j
And if it is double in magnitude: v = 20i + 52j
Hope this helps you! Ask me anything if yu have any quistions!
The function and the first value stated for x are confusing.
Doing some research, I found that the problem is to evaluate the function

for x = - 1 and x 2.
The solution is:
1) For x = - 1

2) For x = 2
Using the quadratic equation we get:

Factoring out 2 we get

Factoring out the imaginary number:

So b.
Every point on the x-axis has y-coordinate 0.
Let y = 0, and solve for x.
y = -5x + 5
0 = -5x + 5
5x = 5
x = 1
The line crosses the x-axis at x = 1.