The probability of getting heads on a coin toss is
0.5
The probability of choosing a number <u>less</u> than four is
3/10 (1,2,3)
Therefore, the probability of getting heads <u>and</u> choosing a number less than four is:
![= \frac{1}{2} (\frac{3}{10}) = \frac{3}{20} = 0.15](https://tex.z-dn.net/?f=%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%28%5Cfrac%7B3%7D%7B10%7D%29%20%3D%20%5Cfrac%7B3%7D%7B20%7D%20%3D%200.15)
Hope this helps!
The rate of change is 8/6.
Answer:
The answer to your question is
sin Ф = 0.731 and sinФ = -0.731; cos Ф 0.682 and cos Ф = -0.682
Step-by-step explanation:
tan Ф = 1.072, 0 < Ф < 2 π, tan Ф is positive, find the solution in the first and third quadrangle.
- tan Ф = opposite side / adjacent side
- 1.072 / 1 = opposite side / adjacent side
- opposite side = 1.072 and adjacent side = 1
Calculate hypotenuse
c² = a² + b²
c² = 1.072² + 1²
c² = 2.149
hypotenuse = c = 1.466
First quadrangle
sin Ф = 1.072 / 1.466 = 0.731
cos Ф = 1 / 1.466 = 0.682
Third quadrangle
sin Ф = -1.072 / 1.466 = -0.731
cos Ф = -1 / 1.466 = -0.682