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3 years ago

Which is a solution to (x-2)(x+10)=13

Mathematics

2 answers:

Marina CMI [18]3 years ago

7 0

Answer:

A. -3

Step-by-step explanation:

I took the test on edge.

STALIN [3.7K]3 years ago

6 0

Answer:

make An equation for both of the numbers in the parentheses .

Step-by-step explanation:

this is how it should look x -2 would be x =15, because you add 2 on both sides , now you have x=15 which should be the answer because 15 is now x and 15 minus 2 = 13

now for the second one

first subtract 10 on both sides then you should get the answer X equals three the reason why it’s like that is because 3 is now x and 3 + 10 = 13.

Hope this helped have a good day :D

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If f(2) = 13 and f '(x) ≥ 3 for 2 ≤ x ≤ 4, how small can f(4) possibly be?

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The slope f'(x) = [f(4) - f(2)]/(4-2)≥3,
so [f(4) - 13]/2 ≥3
f(4) -13 ≥ 6
f(4)≥19, so it can be as small as 19.

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3 years ago

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3 years ago

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3 years ago

At a carnival, contestants are asked to keep rolling a pair of dice until they roll snake eyes. The number of rolls needed has a

Stells [14]

Answer:

The two numbers of rolls are 25.2 and 46.8.

Step-by-step explanation:

The Chebyshev's theorem states that, if X is a r.v. with mean µ and standard deviation σ, then for any positive number k, we have

$P (|X -\mu| < k\sigma) \geq (1-\frac{1}{k^{2}})$

Here

$(1-\frac{1}{k^{2}})=0.75\\\\\Rightarrow \frac{1}{k^{2}}=0.25\\\\\Rightarrow k=\sqrt{\frac{1}{0.25}}\\\\\Rightarrow k=2$

Then we know that,

$|X - \mu| \geq k\sigma,\\\\ \Rightarrow \mu - k\sigma \leq X \leq \mu + k\sigma$ .

Here it is given that mean (µ) = 36 and standard deviation (σ) = 5.4.

Compute the two values between which at least 75% of the contestants lie as follows:

$P(\mu - k\sigma \leq X \leq \mu + k\sigma)=0.75\\\\P(36 - 2\cdot\ 5.4 \leq X \leq 36 + 2\cdot\ 5.4)=0.75\\\\P(25.2\leq X\leq 46.8)=0.75$

Thus, the two numbers of rolls are 25.2 and 46.8.

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3 years ago