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3 years ago

13

The water level was -4 feet before rainy season after rainy season the water level was 4 feet by how much did the water level ch

ange

1 answer:

Helen [10]3 years ago

7 0

After rainy season it grew by eight feet

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Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?

Anit [1.1K]

Answer:

$\dfrac{p^{7} q}{160}$

Step-by-step explanation:

$\dfrac{(4p^-4 q)^-2}{10pq^-3} =$

$= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}$

$= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}$

$= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}$

$= \dfrac{1}{160}p^{7} q$

$= \dfrac{p^{7} q}{160}$

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The width of the garden is 78
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A mutual fund has total assets of 2.4 million dollars and 300,000 shares. What is the net asset value of one share of the fund?

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I believe the answer is c. $8. 00

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8.A book is 320 pages long and has an

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2 years ago

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Suppose James randomly draws a card from a standard deck of 52 cards. He then places it back into the deck and draws a second ca

qwelly [4]

Answer:

1.92%

Step-by-step explanation:

The probability for first case, picking a queen out of deck, will be:

$\frac{4}{52}$

as there will be 4 queens in a deck, one of each suit.

For the second pick, the probability of picking a diamond card, will be:

$\frac{13}{52}$

here the total will remain 52 as he has replaced the first card and not kept it aside and there will be 13 cards in diamond suit (including the three face cards).

Thus the net probability for both cases will be:

$P = \frac{4}{52} * \frac{13}{52}\\ P = \frac{1}{52}\\ P = 0.01923\\P = 1.923\%\\\\P = 1.92\%$

Thus total probability for the combined two cases will be 1.92%

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3 years ago