<h3>Answer: </h3>
about 1.768 seconds
<h3>Explanation:</h3>
Since the phone is <em>dropped</em>, the first equation applies. The final height is assumed to be zero, so we have ...
... h(t) = 0 = -16t² +50
... 16t² = 50 . . . . . . . . add 16t²
... t² = 50/16 . . . . . . . . divide by 16
... t = √3.125 . . . . . . . take the square root
... t ≈ 1.768 . . . . . . . . round to milliseconds
There’s no image to show the outliers
Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Answer:
According to my very precise calculations, I've come to the conclusion that the answer is 1.
Answer:
Step-by-step explanation:
Given
- 3 rectangular cards
- each card is 8 inches by 9 inches
The way that she can arrange the cards, without overlapping, to make one larger polygon with the smallest possible perimeter is that:
Put 3 cards together according to the length
So the smallest possible perimeter is:
8 + 8 + 8 + 8 + 8 + 8 + 9 + 9 = 66 inches as you can see in the attached photo.
The area of the polygon is equal to the combined area of the 3 cards without overlapping or extending.
Hope it can find you well.