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Andrej [43]
3 years ago
8

We have 50 video gamers who share information about their favorite games. 20 people say that Borderlands II is their favorite ga

me. 33 say their favorite game is Fortnite, while 19 declare Minecraft as their favorite game (note that a single person can have several favorite games). 15 people say that Borderlands and Fortnite are both favorites, while 10 say that both Borderlands and Minecraft are their favorites. Finally, 5 people declare all 3 of the games as their favorites. How many people declared Minecraft and Fortnite (exclusively) as their favorites?
Mathematics
2 answers:
stealth61 [152]3 years ago
7 0

Answer:

2 people

Step-by-step explanation:

Total number of people (n) = 50

Borderlands II (B) = 20

Fortnite (F) = 33

Minecraft (M) = 19

Borderlands and Fortnite (B&F) = 15

Borderlands and Minecraft (B&M)= 10

All games (B&M&F) = 5

The number of people that claimed more than one game as their favorite (X) is given by:

X=M+B+F-n\\X=19+20+33-50\\X=22\ people

Those people can be divided in B&F only, B&M only, M&F only and B&M&F:

X=(B\&M-B\&M\&F)+(B\&F-B\&M\&F)+(M\&F-B\&M\&F)+B\&M\&F\\X=B\&M+B\&F+M\&F-2*B\&M\&F\\22=10+15+M\&F-2*5\\M\&F=7\ people

7 people claimed that Minecraft and Fortnite were their favorites however, 5 of those people claimed all of the games as their favorite. Therefore, only 2 people declared Minecraft and Fortnite (exclusively) as their favorites.

Wittaler [7]3 years ago
5 0

Answer:

2

Step-by-step explanation:

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Answer:

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

Step-by-step explanation:

1) Data given and notation

n=232 represent the random sample taken

X represent the adults were no longer smoking after one month

\hat p=0.849 estimated proportion of adults were no longer smoking after one month

p_o=0.80 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.8.:  

Null hypothesis:p=0.8  

Alternative hypothesis:p \neq 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

4) Statistical decision  

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The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

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