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Fed [463]
4 years ago
14

For what values of θ, −π ≤ θ ≤ π, is y = tan θ undefined?

Mathematics
1 answer:
pogonyaev4 years ago
3 0

Answer:

The answer is II and IV ⇒ the 3rd answer

Step-by-step explanation:

* lets check the domain of angle Ф

∵ -π ≤ Ф ≤ π

∵ y = tanФ

∵ tanФ = sinФ/cosФ

* The effective term which makes tanФ undefined is cosФ

- If cosФ = 0, than tanФ will be undefined

* Lets check the angles that have cosФ = 0

∵ The unit circle intersect x-axis at point (1 , 0) and (-1 , 0)

∵ The unit circle intersect y-axis at point (0 , 1) and (0 , -1)

∵ cosФ = x-coordinates of the points

∵ The points of intersection with the y-axis have x- coordinates = 0

∴ The angles on the y-axis have cosФ = 0

* The angles on the +ve part of y-axis are π/2 and -3π/2

 The angles on the -ve part of y-axis are -π/2 and 3π/2

∴ The tan of π/2 , 3π/2 , -π/2 , -3π/2 undefined

* In the problem

I. -π ⇒ defined ⇒ on the -ve part of x-axis

II. -π/2 ⇒undefined

III. 0 ⇒ defined ⇒ on the +ve part of the x-axis

IV. π/2 ⇒ undefined

V. π ⇒ defined ⇒ on the -ve part of x-axis

∴ The answer is II and IV ⇒ the 3rd answer

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3 years ago
The football club sold bags of candy and cookies to raise money for the spring show. Bags of candy cost $6.00
faust18 [17]

Answer:

Candy=x=2.8 bags

Cookies=3+2.8=5.8 bags

Step-by-step explanation:

Price

Bag of candy=$6.00

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Let cookies=y=3+x

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Total sales=price*quantity of x + price*quantity of y

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40=12+10x

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6 0
3 years ago
1 3/4 divided by 2 3/8<br><br> will give brainiest pls help
Ivanshal [37]

Answer:

\frac{14}{19}

First:

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Then your initial equation becomes:

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Applying the fractions formula for division:

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Simplifying 56/76, the answer is:

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I hope this helps! :)

8 0
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Eduardwww [97]

20 and 10.

I can't explain this, because of the fact that I have not learned this yet, and I might be wrong. But I hope I'm not and I hope I helped! ☺

6 0
4 years ago
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Score: 0 of 1 pt
jonny [76]

Answer:

See attachment for graph

Step-by-step explanation:

Given

y = x^2 - 3

Required

The graph of the equation

First, we determine the range of y

x = -3

y = x^2 - 3 \to y = (-3)^2 - 3 = 6

(-3,6)

x = -2

y = (-2)^2 - 3 = 1

(-2,1)

x = -1

y = (-1)^2 - 3 = -2

(-1,-2)

x=0

y = 0^2 - 3 = -3

(0,-3)

x = 1

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(1,-2)

x = 2

y =2^2 - 3 = 1

(2,1)

x = 3

y = 3^2 - 3 = 6

(3,6)

<em>See attachment for graph</em>

7 0
3 years ago
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