The solubility product is calculated using the ions that are formed by the dissolution of a solid. Therefore, the reaction for this solubility product expression is:
Ag₂CO₃ → 2Ag⁺ + CO₃⁻²
Answer: Correct statements are given below:
1) In activity series elements are listed according to their reactivity.
2) Nuclear reaction in which low atomic nuclei fuse to form a heavier nucleus with the release of energy. Nuclear fusion reaction occurs in the sun.
3) C3H8 + 5O2 → 3CO2 + 4H2O is the example of a combustion reaction.
4) 2Fe + O2 → 2FeO is the example of synthesis reaction. In synthesis reaction is a type of reaction in which two reactants combine to form a single product.
Explanation:
Metals are the species which readily lose electrons in order to attain stability. This electron lost by the atom is actually present in its outermost shell which is also known as valence shell.
Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.
When we move across a period from left to right then there occurs a decrease in atomic size of the atoms. Therefore, ionization energy increases along a period.
But when we move down a group then there occurs an increase in atomic size of the atoms due to addition of number of electrons in the atoms. Hence, ionization energy decreases along a group.
Thus, we can conclude that metals have low ionization energies and readily share their valence or outer electrons with each other to form an electron sea. These electrons are delocalized or shared among all the atoms that are bonded together and can therefore move freely throughout the metal structure.
I can't give an exact answer if you do not provide any unit of concentration. The most common unit of concentration is molarity, which is the number of moles of solute over the number of liters solution. Say for example, the concentration of the solution is 0.1 M. To find the equivalent mass percentage, the solution is as follows:
The molar mass of Sr(NO₃)₂ is <span>211.63 g/mol.
(0.1 mol </span>Sr(NO₃)₂/ L solution)(211.63 g/mol)(1 L solution/ 1 kg solution)(1 kg/1000 g solution) * 100 = <em>2.12% Sr(NO₃)₂ solution</em>