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Maksim231197 [3]
2 years ago
7

How many cubic miles are 8.48E+08 gallons of water? The density of water at ambient conditions is 1.000 g/mL.

Chemistry
1 answer:
Inessa05 [86]2 years ago
7 0

The volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .

<h3>Weight of one gallon of water</h3>

The weight of 1 gal of water is given as 3785 g

Mass of 8.48 x 10⁸ gal = 3785 x 8.48 x 10⁸ = 3.2 x 10¹² g

<h3>Volume of the water in cubic meters</h3>

Volume = mass/density

Volume = 3.2 x 10¹² g/1 gmL

Volume = 3.2 x 10¹² mL x 10⁻⁶ m³/mL = 3.2 x 10⁶ m³

Thus, the volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .

Learn more about volume here: brainly.com/question/1972490

#SPJ1

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How many grams in 4.53 moles of MgBr2
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The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−
barxatty [35]

Answer:

The reaction will be  non spontaneous at these concentrations.

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AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)

Expression for an equilibrium constant K_c:

K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]

Solubility product of the reaction:

K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}

Reaction between Gibb's free energy and equilibrium constant if given as:

\Delta G^o=-2.303\times R\times T\times \log K_c

\Delta G^o=-2.303\times R\times T\times \log K_{sp}

\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]

\Delta G^o=69,117.84 J/mol=69.117 kJ/mol

Gibb's free energy when concentration [Ag^+] = 1.0\times 10^{-2} M and [Br^-] = 1.0\times 10^{-3} M

Reaction quotient of an equilibrium = Q

Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}

\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)

\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])

\Delta G=40.588 kJ/mol

  • For reaction to spontaneous reaction:  \Delta G.
  • For reaction to non spontaneous reaction:  \Delta G>0.

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0
2 years ago
Un deportista de 72 kg trepa por una cuerda hasta una altura de 12m. Calcula el incremento de energía potencial gravitatoria que
Oxana [17]

A 72 kg athlete climbs a rope to a height of 12m. Calculate the increase in gravitational potential energy it has experienced.

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8467.2J

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Given parameters:

Mass of the athlete = 72kg

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Increase in gravitational potential energy it has experienced = ?

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Gravitational potential energy is the energy due to the position of a body. It is mathematically expressed as;

  Gravitational potential energy  = m x g x h

m is the mass

g is the acceleration due to gravity  = 9.8m/s²

h is the height

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