Answer:
0 M.
Explanation:
Hello,
In this case, the undergoing reaction is:
![M(NO_3)_2+NaCN\leftrightarrow [M(CN)_4]^{-2}+NaNO_3](https://tex.z-dn.net/?f=M%28NO_3%29_2%2BNaCN%5Cleftrightarrow%20%5BM%28CN%29_4%5D%5E%7B-2%7D%2BNaNO_3)
Nonetheless, it only matters the reaction forming the given complex:
![M^{+2}+4CN^-\leftrightarrow [M(CN)_4]^{-2}](https://tex.z-dn.net/?f=M%5E%7B%2B2%7D%2B4CN%5E-%5Cleftrightarrow%20%5BM%28CN%29_4%5D%5E%7B-2%7D)
In such a way, the formation constant turns out:
![K_F=\frac{[[M(CN)_4]^{-2}]_{eq}}{[M^{+2}]_{eq}[CN^{-}]_{eq}^4}](https://tex.z-dn.net/?f=K_F%3D%5Cfrac%7B%5B%5BM%28CN%29_4%5D%5E%7B-2%7D%5D_%7Beq%7D%7D%7B%5BM%5E%7B%2B2%7D%5D_%7Beq%7D%5BCN%5E%7B-%7D%5D_%7Beq%7D%5E4%7D)
Now, one could assume that the initial concentrations of the ions equals the original compounds concentrations:
![[M^{+2}]_0=0.150M;[CN^-]_0=0.820M](https://tex.z-dn.net/?f=%5BM%5E%7B%2B2%7D%5D_0%3D0.150M%3B%5BCN%5E-%5D_0%3D0.820M)
In such a way, we modify the formation constant in terms of the change 
due to the reaction progress:
Now, solving for :
The feasible solution is 0.15M which will lead to an equilibrium concentration of M⁺² of 0M
![[M^{+2}]_{eq}=0.15M-0.15M=0M](https://tex.z-dn.net/?f=%5BM%5E%7B%2B2%7D%5D_%7Beq%7D%3D0.15M-0.15M%3D0M)
This fact has sense since the formation constant is very large.
Best regards.
It reflects sunlight. It's a physical barrier (in comparison to some sunscreens which are chemical blocks). Sunlight is mostly white light and zinc oxide reflects white light
An organic compound<span> is any member of a large class of gaseous, liquid, or solid chemical </span>compounds whose molecules contain carbon and <span>a hydrocarbon is compound of hydrogen and carbon, such as any of those that are the chief components of petroleum and natural gas.</span>
<u>We want the molar mass (gfm) of Fe and FeS.</u>
Fe = 55.8 g/mol and FeS = 87.8 g/mol (55.8 +32.0).
<u>Explanation:</u>
We want ratio between Fe:FeS 8:8. This comes from the coefficients of the equal chemical equation.
Now we set up conversion factors following the roadmap from above.
Unit we want in the numerator, unit to cancel in the denominator.
Multiply the numerators, and divide the denominators.
The outcome is 243.82 g of ferrous sulphite
By the above given formula we can find any amount of Fes produced by any amount of ferrous react with sulphite.
B. Infrared light I'm pretty sure correct me if I am wrong hope this helped
