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goldenfox [79]
3 years ago
12

At a constant temperature a container of helium gas with an unknown volume changes pressure from 1 atm to 2 atm. If at 2 atm the

volume is 15 L what is the original volume of the container?
Chemistry
1 answer:
ycow [4]3 years ago
5 0

Answer:

7.5 L

Explanation:

Use Boyle's Law and rearrange formula.

- Hope this helps! Please let me know if you need further explanation.

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hydrated CoCl2 is a deep purple color. After being heated for a long time, it turns into its anhydrous form, which is sky blue.
ch4aika [34]

Answer:

Physical change

Explanation:

It is a physical change because a physical change involves alteration in physical properties or appearance in color, sizes e.t.c but no new substances is formed. From the question, CoCl2 undergo a physical change because it's physical property which is color changed , its composition is not altered or no new substances is formed during the reaction.

6 0
3 years ago
Each day one astronaut exhales about 448 L of carbon dioxide. how many grams of LiOH is needed to remvoe this much carboon dioxi
Romashka [77]

Answer:

How to determine the mole of LiOH required to react with 20 moles of CO₂ per day

CO₂ + 2LiOH —> Li₂CO₃ + H₂O

From the balanced equation above,

1 mole of CO₂  required 2 moles of LiOH.

Therefore,

20 moles of CO₂ will require = 20 × 2 = 40 moles of LiOH

How to determine the mole of LiOH required by two astronauts for 3 days

Mole of LiOH for 1 person per day = 40 moles

Mole of LiOH for 2 persons per day = 2 × 40 = 80 moles

Mole of LiOH for 2 persons for 3 days = 80 × 3 = 240 moles

Explanation:

mark brainliest

7 0
2 years ago
HURRY NOW Scince 20 points
Murljashka [212]
I am also pretty sure the answer is B, but give the answer above me Brainliest. Have a great day
4 0
3 years ago
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Which type of land biome is created and/orsubstained by a rain shadow
lana [24]
If you can’t figure it out You should l look it up in the internet
7 0
4 years ago
The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 mL of bromine
Viefleur [7K]

Answer:

16.2 J

Explanation:

Step 1: Given data

  • Specific heat of liquid bromine (c): 0.226 J/g.K
  • Volume of bromine (V): 10.0 mL
  • Initial temperature: 25.00 °C
  • Final temperature: 27.30 °C
  • Density of bromine (ρ): 3.12 g/mL

Step 2: Calculate the mass of bromine

The density is equal to the mass divided by the volume.

ρ = m/V

m = ρ × V

m = 3.12 g/mL × 10.0 mL

m = 31.2 g

Step 3: Calculate the change in the temperature (ΔT)

ΔT = 27.30 °C - 25.00 °C = 2.30 °C

The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.

Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine

We will use the following expression.

Q = c × m × ΔT

Q = 0.226 J/g.K × 31.2 g × 2.30 K

Q = 16.2 J

7 0
3 years ago
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