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3 years ago

For the system of equations shown below

1 answer:

4 0

2x=-y+6
-4x+3y=8
Rewriting the equations;
y+2x=6
3y-4x=8

Multiplying equation I by 3;
3y+6x=18
3y-4x=8
Subtracting equation II from equation I;
10x=10
x=1

Replacing for x in the first equation;
2x=-y+6
2(1)=-y+6
2=-y+6
2-6=-y
-4=-y
y=4

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Writing an equation of a line given its slope and y-intercept

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Read 2 more answers

1. Kristen spent $131 on shirts at Target last week. She bought some fancy shirts for

Masja [62]

Answer:

Kristen bought 2 fancy shirts and 5 plain t-shirts.

Step-by-step explanation:

Given that,

Kristen spent $131 on 7 shirts.

Cost of one fancy shirt = $28

Cost of one plain t-shirt = $15

Let,

x be the number of fancy shirts

y be the number of plain t-shirts

x+y = 7 Eqn 1

28x+15y=131 Eqn 2

Multiplying Eqn 1 by 15

15(x+y=7)

15x+15y=105 Eqn 3

Subtracting Eqn 3 from Eqn 2

(28x+15y)-(15x+15y)=131-105

28x+15y-15x+15y=26

13x=26

Dividing both sides by 13

$\frac{13x}{13}=\frac{26}{13}\\x=2$

Putting x=2 in Eqn 1

2+y=7

y=7-2

y=5

Hence,

Kristen bought 2 fancy shirts and 5 plain t-shirts.

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3 years ago

What is 325 percent of 220

nikitadnepr [17]

Answer:

Step-by-step explanation:

325/220×100≈147.73

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3 years ago

I dont know the answer

Oduvanchick [21]

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3 years ago

Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

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3 years ago