Answer:
0.10013 atm
Explanation:
Applying Boyle's Law,
P'V' = PV................... Equation 1
Where P' = Initial pressure of air, V' = Initial volume of air, P = Final pressure of air, V = Final volume of air.
make P the subject of the equation
P = P'V'/V..................... Equation 2
Given: P' = 0.355 atm, V' 0.110 m³, V = 0.390 m³
Substitute into equation 2
P = 0.355(0.11)/0.39
P = 0.10013 atm.
Answer:
when the reflecting surface is plain and without even small hurdles that are not the visible by our naked eyes. Eg : plain mirror
Explanation:
A joule is one Newton of force applied over a meter.
For every meter, the brakes put 240000N of force (N=Newtons).
For 40m, multiply the Newtons by 40.
240000N*40=9600000N
To solve this problem we will apply the concepts related to equilibrium, for this specific case, through the sum of torques.
If the distance in which the 600lb are applied is 6in, we will have to add the unknown Force sum, at a distance of 27in - 6in will be equivalent to that required to move the object. So,
So, Force that must be applied at the long end in order to lift a 600lb object to the short end is 171.42lb
Answer:
<u>Example of Newton's III law</u>
- In the, golf the ball was hit by a club with certain force. As the club hits the ball it's the action. When the ball flies away its the reaction.
- When a person swings a golf club at the ball, when it hits the ball, it causes the ball to roll up the face of the club and into the air towards the target.
